Lucas conducted a dihybrid cross in his genetics experiment. He observed 315 flies with gray body and long wings, 108 flies with gray body and miniature wings, 101 flies with ebony body and long wings, and 32 flies with ebony body and miniature wings. Analyse these data using test to see if (i) they fit a 9:3:3:1 ratio. (ii) the gray : ebony data fit a 3:1 ratio. Table 1: Chi-square table Chi Square Values and Probability Degrees of Freedom P= 0.99 0.95 0.80 0.50 0.20 0.05 0.01 1 0.000157 0.00393 0.0642 0.455 1.642 3.841 6.635 2 0.020 0.103 0.446 1.386 3.219 5.991 9.210 3 0.115 0.352 1.005 2.366 4.642 7.815 11.345 4 0.297 0.711 1.649 3.357 5.989 9.488 13.277
Lucas conducted a dihybrid cross in his genetics experiment. He observed 315 flies with gray body and long wings, 108 flies with gray body and miniature wings, 101 flies with ebony body and long wings, and 32 flies with ebony body and miniature wings. Analyse these data using test to see if (i) they fit a 9:3:3:1 ratio. (ii) the gray : ebony data fit a 3:1 ratio. Table 1: Chi-square table Chi Square Values and Probability Degrees of Freedom P= 0.99 0.95 0.80 0.50 0.20 0.05 0.01 1 0.000157 0.00393 0.0642 0.455 1.642 3.841 6.635 2 0.020 0.103 0.446 1.386 3.219 5.991 9.210 3 0.115 0.352 1.005 2.366 4.642 7.815 11.345 4 0.297 0.711 1.649 3.357 5.989 9.488 13.277
Human Anatomy & Physiology (11th Edition)
11th Edition
ISBN:9780134580999
Author:Elaine N. Marieb, Katja N. Hoehn
Publisher:Elaine N. Marieb, Katja N. Hoehn
Chapter1: The Human Body: An Orientation
Section: Chapter Questions
Problem 1RQ: The correct sequence of levels forming the structural hierarchy is A. (a) organ, organ system,...
Related questions
Question
![Lucas conducted a dihybrid cross in his genetics experiment. He observed 315 flies with gray
body and long wings, 108 flies with gray body and miniature wings, 101 flies with ebony body
and long wings, and 32 flies with ebony body and miniature wings. Analyse these data using
test to see if
(i)
they fit a 9:3:3:1 ratio.
(ii)
the gray : ebony data fit a 3:1 ratio.
Table 1: Chi-square table
Chi Square Values and Probability
Degrees of
Freedom
P = 0.99
0.95
0.80
0.50
0.20
0.05
0.01
0.000157
0.00393
0.0642
0.455
1.642
3.841
6.635
2
0.020
0.103
0.446
1.386
3.219
5.991
9.210
0.115
0.352
1.005
2.366
4.642
7.815
11.345
4.
0.297
0.711
1.649
3.357
5.989
9.488
13.277](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fcb34c98a-284d-4b54-bafe-5bf03cf092c1%2Fd5b95c7f-1055-4e76-82a1-6bfbe51883ff%2F34kjbit_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Lucas conducted a dihybrid cross in his genetics experiment. He observed 315 flies with gray
body and long wings, 108 flies with gray body and miniature wings, 101 flies with ebony body
and long wings, and 32 flies with ebony body and miniature wings. Analyse these data using
test to see if
(i)
they fit a 9:3:3:1 ratio.
(ii)
the gray : ebony data fit a 3:1 ratio.
Table 1: Chi-square table
Chi Square Values and Probability
Degrees of
Freedom
P = 0.99
0.95
0.80
0.50
0.20
0.05
0.01
0.000157
0.00393
0.0642
0.455
1.642
3.841
6.635
2
0.020
0.103
0.446
1.386
3.219
5.991
9.210
0.115
0.352
1.005
2.366
4.642
7.815
11.345
4.
0.297
0.711
1.649
3.357
5.989
9.488
13.277
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