Listen The data in the table below were obtained for the reaction: H2 (g) + 12 (g) Experiment Number 1 2 3 - 2 HI(g) [H₂] (M) [12] (M) 0.10 0.40 0.10 0.100 0.100 0.300 Initial Rate (M/s) 0.0050 0.080 0.045 Using the Rate law determined from this data. What is the rate if [H₂] = 0.25 [12] = 0.305M
Listen The data in the table below were obtained for the reaction: H2 (g) + 12 (g) Experiment Number 1 2 3 - 2 HI(g) [H₂] (M) [12] (M) 0.10 0.40 0.10 0.100 0.100 0.300 Initial Rate (M/s) 0.0050 0.080 0.045 Using the Rate law determined from this data. What is the rate if [H₂] = 0.25 [12] = 0.305M
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![Page 1:
2:
E
1) Listen
The data in the table below were obtained for the reaction:
H2 (g) + 12 (g) → 2 HI(g)
Experiment
Number [H₂] (M)
123
0.100
0.100
0.300
0.29 M/s
0.031 M/s
0.291 M/s
O.0291 M/s
0.029 M/s
[12₂] (M)
0.10
0.40
0.10
Initial Rate
(M/s)
0.0050
0.080
0.045
188
AT
Using the Rate law determined from this data. What is the rate if [H₂] = 0.25
[12] = 0.305M](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9a8b552d-fc99-43ee-ac78-e0167991c522%2F7ffd588e-aae4-40c0-8616-d9d1258c12c1%2Fqsl64yn_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Page 1:
2:
E
1) Listen
The data in the table below were obtained for the reaction:
H2 (g) + 12 (g) → 2 HI(g)
Experiment
Number [H₂] (M)
123
0.100
0.100
0.300
0.29 M/s
0.031 M/s
0.291 M/s
O.0291 M/s
0.029 M/s
[12₂] (M)
0.10
0.40
0.10
Initial Rate
(M/s)
0.0050
0.080
0.045
188
AT
Using the Rate law determined from this data. What is the rate if [H₂] = 0.25
[12] = 0.305M
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