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Listed in the data table are amounts of strontium-90 (in millibecquerels, or mBq, per gram of calcium) in a simple random sample of baby teeth obtained from resident n two cities. Assume that the two samples are independent simple random samples selected from normally distributed populations. Do not assume that the populatio standard deviations are equal. Use a 0.01 significance level to test the claim that the mean amount of strontium-90 from city #1 residents is greater than the mean amount from city #2 residents. Click the icon to view the data table of strontium-90 amounts. What are the null and alternative hypotheses? Assume that population 1 consists of amounts from city #1 levels and population 2 consists of amounts from city #2. O A. Ho: H1 SH2 H:H> H2 O B. Ho: H1 H2 H: H1> H2 O D. Ho: H1 = H2 H: H> H2 OC. Ho: H1 = H2 H: H1 H2 The test statistic is (Round to two decimal places as needed.) The P-value is (Round to three decimal places as needpd.) State the conclusion for the test. OA. Fail to reject the null hypothesis. There is sufficient evidence to support the claim that the mean amount of strontium-90 from city #1 residents is greater. O B. Fail to reject the null hypothesis. There is not sufficient evidence to support the claim that the mean amount of strontium-90 from city #1 residents is greater. OC. Reject the null hypothesis. There is sufficient evidence to support the claim that the mean amount of strontium-90 from city #1 residents is greater. O D. Reject the null hypothesis. There is not sufficient evidence to support the claim that the mean amount of strontium-90 from city #1 residents is greater.

Listed in the data table are amounts of strontium-90 (in millibecquerels, or mBq, per gram of calcium) in a simple random sample of baby teeth obtained from resident n two cities. Assume that the two samples are independent simple random samples selected from normally distributed populations. Do not assume that the populatio standard deviations are equal. Use a 0.01 significance level to test the claim that the mean amount of strontium-90 from city #1 residents is greater than the mean amount from city #2 residents. Click the icon to view the data table of strontium-90 amounts. What are the null and alternative hypotheses? Assume that population 1 consists of amounts from city #1 levels and population 2 consists of amounts from city #2. O A. Ho: H1 SH2 H:H> H2 O B. Ho: H1 H2 H: H1> H2 O D. Ho: H1 = H2 H: H> H2 OC. Ho: H1 = H2 H: H1 H2 The test statistic is (Round to two decimal places as needed.) The P-value is (Round to three decimal places as needpd.) State the conclusion for the test. OA. Fail to reject the null hypothesis. There is sufficient evidence to support the claim that the mean amount of strontium-90 from city #1 residents is greater. O B. Fail to reject the null hypothesis. There is not sufficient evidence to support the claim that the mean amount of strontium-90 from city #1 residents is greater. OC. Reject the null hypothesis. There is sufficient evidence to support the claim that the mean amount of strontium-90 from city #1 residents is greater. O D. Reject the null hypothesis. There is not sufficient evidence to support the claim that the mean amount of strontium-90 from city #1 residents is greater.

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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This Questiön! Listed in the data table are amounts of strontium-90 (in millibecquerels, or mBq, per gram of calcium) in a simple random sample of baby teeth obtained from residents in two cities. Assume that the two samples are independent simple random samples selected from normally distributed populations. Do not assume that the population standard deviations are equal. Use a 0.01 significance level to test the claim that the mean amount of strontium-90 from city #1 residents is greater than the mean amount from city #2 residents. Click the icon to view the data table of strontium-90 amounts. What are the null and alternative hypotheses? ASsume that population 1 consists of amounts from city #1 levels and population 2 consists of amounts from city #2. O A. Ho: H1 SH2 H,: Hq> Hz O B. Ho: H1 #H2 Hi: Hy> H2 OC. Ho: H1 = H2 O D. Ho: H1 = H2 The test statistic is (Round to two decimal places as needed.) The P-value is- (Round to three decimal places as needd.) State the conclusion for the test. A. Fail to reject the null hypothesis. There is sufficient evidence to support the claim that the mean amount of strontium-90 from city #1 residents is greater. B. Fail to reject the null hypothesis. There is not sufficient evidence to support the claim that the mean amount of strontium-90 from city #1 residents is greater. C. Reject the null hypothesis. There is sufficient evidence to support the claim that the mean amount of strontium-90 from city #1 residents is greater. D. Reject the null hypothesis. There is not sufficient evidence to support the claim that the mean amount of strontium-90 from city #1 residents is greater. Click to select your answer(s). 337 NOV 30 W étv S
Transcribed Image Text:This Questiön! Listed in the data table are amounts of strontium-90 (in millibecquerels, or mBq, per gram of calcium) in a simple random sample of baby teeth obtained from residents in two cities. Assume that the two samples are independent simple random samples selected from normally distributed populations. Do not assume that the population standard deviations are equal. Use a 0.01 significance level to test the claim that the mean amount of strontium-90 from city #1 residents is greater than the mean amount from city #2 residents. Click the icon to view the data table of strontium-90 amounts. What are the null and alternative hypotheses? ASsume that population 1 consists of amounts from city #1 levels and population 2 consists of amounts from city #2. O A. Ho: H1 SH2 H,: Hq> Hz O B. Ho: H1 #H2 Hi: Hy> H2 OC. Ho: H1 = H2 O D. Ho: H1 = H2 The test statistic is (Round to two decimal places as needed.) The P-value is- (Round to three decimal places as needd.) State the conclusion for the test. A. Fail to reject the null hypothesis. There is sufficient evidence to support the claim that the mean amount of strontium-90 from city #1 residents is greater. B. Fail to reject the null hypothesis. There is not sufficient evidence to support the claim that the mean amount of strontium-90 from city #1 residents is greater. C. Reject the null hypothesis. There is sufficient evidence to support the claim that the mean amount of strontium-90 from city #1 residents is greater. D. Reject the null hypothesis. There is not sufficient evidence to support the claim that the mean amount of strontium-90 from city #1 residents is greater. Click to select your answer(s). 337 NOV 30 W étv S
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