Listed in the accompanying data table are student evaluation ratings of courses and professors, where a rating of 5 is for "excellent." Assume that each sample is a simple random sample obtained from a population with a normal distribution. Use the 93 course evaluations to construct a 99% confidence interval estimate of the standard deviation of the population from which the sample was obtained. < σ < (Round to two decimal places as needed.) Repeat part (a) using the 93 professor evaluations. < σ < (Round to two decimal places as needed.) Compare the results. Choose the correct answer below. The intervals overlap, so the populations appear to have amounts of variation that are not substantially different. The intervals do not overlap, so the populations appear to have amounts of variation that are not substantially different. The intervals do not overlap, so the populations appear to have amounts of variation that are substantially different. The professor evaluations have a significantly larger population standard deviation than the course evaluations. The results cannot be directly compared. The intervals do not overlap, so the populations appear to have amounts of variation that are substantially different. The course evaluations have a significantly larger population standard deviation than the professor evaluations. The intervals overlap, so the populations appear to have amounts of variation that are substantially different. Course Eval Prof Eval 4.5 5.0 4.5 4.6 3.6 4.4 4.4 4.3 4.5 5.1 4.3 4.1 4.1 4.6 3.6 3.3 5.0 4.8 4.0 4.2 2.9 3.9 3.7 4.1 3.9 3.9 3.3 3.4 3.1 3.2 4.6 4.7 4.0 4.1 4.1 3.7 4.1 4.7 3.5 3.8 3.2 3.5 3.2 3.1 4.1 4.4 4.3 4.6 3.9 4.3 4.9 5.1 4.1 4.4 3.9 4.2 3.1 3.7 4.4 4.6 2.5 2.4 3.7 4.4 4.8 4.9 3.6 4.2 4.1 4.1 4.1 4.0 3.7 3.8 3.6 4.2 4.3 4.2 4.6 5.0 3.6 3.5 4.8 4.1 3.7 3.5 4.0 4.1 4.6 4.4 4.9 4.9 3.3 3.5 3.7 3.9 3.9 4.5 3.9 4.1 4.7 4.7 4.0 4.5 4.7 4.8 3.8 4.0 3.4 3.6 3.4 4.1 4.1 3.9 4.1 4.2 3.3 3.9 3.1 3.5 3.9 4.3 4.3 4.3 3.9 3.5 3.1 3.8 4.3 4.4 3.8 4.0 4.4 4.6 2.2 2.4 2.9 3.3 4.2 4.3 3.6 3.6 4.4 4.6 3.7 4.1 4.0 3.8 3.5 3.6 4.5 4.3 4.4 5.0 4.1 4.2 4.0 3.9 5.1 4.7 3.2 3.5 3.6 3.5 3.6 4.4 5.0 4.9 5.1 4.6 4.3 4.6 3.2 3.1 3.6 3.2 3.6 3.4 3.9 4.4 4.1 3.7 4.0 4.6 3.1 3.6

Listed in the accompanying data table are student evaluation ratings of courses and professors, where a rating of 5 is for "excellent." Assume that each sample is a simple random sample obtained from a population with a normal distribution. Use the 93 course evaluations to construct a 99% confidence interval estimate of the standard deviation of the population from which the sample was obtained. < σ < (Round to two decimal places as needed.) Repeat part (a) using the 93 professor evaluations. < σ < (Round to two decimal places as needed.) Compare the results. Choose the correct answer below. The intervals overlap, so the populations appear to have amounts of variation that are not substantially different. The intervals do not overlap, so the populations appear to have amounts of variation that are not substantially different. The intervals do not overlap, so the populations appear to have amounts of variation that are substantially different. The professor evaluations have a significantly larger population standard deviation than the course evaluations. The results cannot be directly compared. The intervals do not overlap, so the populations appear to have amounts of variation that are substantially different. The course evaluations have a significantly larger population standard deviation than the professor evaluations. The intervals overlap, so the populations appear to have amounts of variation that are substantially different. Course Eval Prof Eval 4.5 5.0 4.5 4.6 3.6 4.4 4.4 4.3 4.5 5.1 4.3 4.1 4.1 4.6 3.6 3.3 5.0 4.8 4.0 4.2 2.9 3.9 3.7 4.1 3.9 3.9 3.3 3.4 3.1 3.2 4.6 4.7 4.0 4.1 4.1 3.7 4.1 4.7 3.5 3.8 3.2 3.5 3.2 3.1 4.1 4.4 4.3 4.6 3.9 4.3 4.9 5.1 4.1 4.4 3.9 4.2 3.1 3.7 4.4 4.6 2.5 2.4 3.7 4.4 4.8 4.9 3.6 4.2 4.1 4.1 4.1 4.0 3.7 3.8 3.6 4.2 4.3 4.2 4.6 5.0 3.6 3.5 4.8 4.1 3.7 3.5 4.0 4.1 4.6 4.4 4.9 4.9 3.3 3.5 3.7 3.9 3.9 4.5 3.9 4.1 4.7 4.7 4.0 4.5 4.7 4.8 3.8 4.0 3.4 3.6 3.4 4.1 4.1 3.9 4.1 4.2 3.3 3.9 3.1 3.5 3.9 4.3 4.3 4.3 3.9 3.5 3.1 3.8 4.3 4.4 3.8 4.0 4.4 4.6 2.2 2.4 2.9 3.3 4.2 4.3 3.6 3.6 4.4 4.6 3.7 4.1 4.0 3.8 3.5 3.6 4.5 4.3 4.4 5.0 4.1 4.2 4.0 3.9 5.1 4.7 3.2 3.5 3.6 3.5 3.6 4.4 5.0 4.9 5.1 4.6 4.3 4.6 3.2 3.1 3.6 3.2 3.6 3.4 3.9 4.4 4.1 3.7 4.0 4.6 3.1 3.6

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Related questions

Question

100%

Use the 93 course evaluations to construct a 99% confidence interval estimate of the standard deviation of the population from which the sample was obtained.

< σ <

(Round to two decimal places as needed.)

Repeat part (a) using the 93 professor evaluations.

< σ <

(Round to two decimal places as needed.)

Compare the results. Choose the correct answer below.

The intervals overlap, so the populations appear to have amounts of variation that are not substantially different.
The intervals do not overlap, so the populations appear to have amounts of variation that are not substantially different.
The intervals do not overlap, so the populations appear to have amounts of variation that are substantially different. The professor evaluations have a significantly larger population standard deviation than the course evaluations.
The results cannot be directly compared.
The intervals do not overlap, so the populations appear to have amounts of variation that are substantially different. The course evaluations have a significantly larger population standard deviation than the professor evaluations.
The intervals overlap, so the populations appear to have amounts of variation that are substantially different.

Course Eval Prof Eval
4.5 5.0
4.5 4.6
3.6 4.4
4.4 4.3
4.5 5.1
4.3 4.1
4.1 4.6
3.6 3.3
5.0 4.8
4.0 4.2
2.9 3.9
3.7 4.1
3.9 3.9
3.3 3.4
3.1 3.2
4.6 4.7
4.0 4.1
4.1 3.7
4.1 4.7
3.5 3.8
3.2 3.5
3.2 3.1
4.1 4.4
4.3 4.6
3.9 4.3
4.9 5.1
4.1 4.4
3.9 4.2
3.1 3.7
4.4 4.6
2.5 2.4
3.7 4.4
4.8 4.9
3.6 4.2
4.1 4.1
4.1 4.0
3.7 3.8
3.6 4.2
4.3 4.2
4.6 5.0
3.6 3.5
4.8 4.1
3.7 3.5
4.0 4.1
4.6 4.4
4.9 4.9
3.3 3.5
3.7 3.9
3.9 4.5
3.9 4.1
4.7 4.7
4.0 4.5
4.7 4.8
3.8 4.0
3.4 3.6
3.4 4.1
4.1 3.9
4.1 4.2
3.3 3.9
3.1 3.5
3.9 4.3
4.3 4.3
3.9 3.5
3.1 3.8
4.3 4.4
3.8 4.0
4.4 4.6
2.2 2.4
2.9 3.3
4.2 4.3
3.6 3.6
4.4 4.6
3.7 4.1
4.0 3.8
3.5 3.6
4.5 4.3
4.4 5.0
4.1 4.2
4.0 3.9
5.1 4.7
3.2 3.5
3.6 3.5
3.6 4.4
5.0 4.9
5.1 4.6
4.3 4.6
3.2 3.1
3.6 3.2
3.6 3.4
3.9 4.4
4.1 3.7
4.0 4.6
3.1 3.6

Features Features Normal distribution is characterized by two parameters, mean (µ) and standard deviation (σ). When graphed, the mean represents the center of the bell curve and the graph is perfectly symmetric about the center. The mean, median, and mode are all equal for a normal distribution. The standard deviation measures the data's spread from the center. The higher the standard deviation, the more the data is spread out and the flatter the bell curve looks. Variance is another commonly used measure of the spread of the distribution and is equal to the square of the standard deviation.

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