Let x be a vector. How do you use rotate(deg) to find a vector y that is normal to x? Namely = 0
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- Code in C. Solve the code below. write a function that receives a vector of integers already sorted in ascending order, an integer n represents the number of elements in this vector, and an integer b. Implement the sequential search algorithm to look for the integer b in the vector. The binary search works as follows: you must look for the element in the position exactly in the half of the vector, if for the searched it returns the number of tests done so far, if not for the searched, calculate the midpoint of the half of the vector after assess whether the searched value is greater or less than the value at the middle position. Not finding the value searched, the function must return 0. The name of the function will be called "busca_bin". int busca_bin (int vetor [ ], int n, int b){ #include <stdio.h> int busca_bin(int vetor[] , int n , int a) { int s1 = 0; int s2 = n-1; int pass = 0; int s3; while(s1<s2) { s3 = (s1+s2)/2; pass++;…Code in C. Solve the code below. Write a function that takes a vector of integers, an integer n representing the number of elements in that vector, and an integer b. Implement the sequential search algorithm to look for the integer b in the vector. The sequential search works as follows: you must look at all the elements of the vector until you find the b, from the first to the last. The function must return an integer representing how many elements the function tested until it found b. If it does not find the function, it must return 0. The name of the function must be called "busca_seq". int busca_seq(int vetor[], int n, int b) { //your code } My Code #include<stdio.h> int busca_seq(int vetor[], int n, int b) { int i; for(i = 0; i < n; i++){ if(vetor[i] == b) return (i+1); } { int vet[5],n = 5,b,x; vet[0] = 1; vet[1] = 2; vet[2] = 3; vet[3] = 4; vet[4] = 5; scanf("%d",&b); x = busca_seq(vet,n,b); printf("%d",x); return 0; } }Function: randOps Input: (1xN double) A Vector of numbers (N>=2 and even) Output: (double) A number Function Description: Given a 1XN vector where N>=2 and even, perform the following random operations in the following order and return the resulting number 1. Extract all even indexed values into a vector and multiply them by 3 2. Extract all odd indexed values into a vector and divide by 5 3. Subtract the results of Step 2 from the results of Step 1. 4. Calculate the product of all the values contained in the vector result of Step 3. 5. Calculate the value needed to get the number from Step 4 to the next highest integer. 6. Round your result from Step 5 to 5 decimal places Hint(s): ▪ prod(), ceil() and round() may be Examples: ans1 = randOps ([2 5 4 1 3 4 2 1]) >>ans1 = 0.9632 ans2 = randOps ([3 6 2 5]) >> ans2 = 0.9600 ans3 = randOps ([30 40 10 20 50 80]) >> ans3 = 0
- How is a double-valued vector created? How can a vector have a double attached to it? What is the most effective method for calculating a vector's size? How should a vector element be removed?Question kh Using R codeI have a vector labeled Dengue_Vec. I need to code a for loop that will provide me with the number of characters in that vector. The characters are nucleotides so they are letters. -The first image is the clear question and the second one is while loop referenced in the question. thank you (I mainly don't understand how to iterate over nonnumerical values in a vector using the for loop or the while loop).
- If you have a vector A-[l 3 5 7 lo] Con Jou Conver it to Column ?numStudents is read from input as the number of input values in the vector that follow. Use two for loops to output all numStudents elements of vector walkingLogs that are: even integers • odd integers ● For both loops, follow each element with a space, including the last element, and end with a newline. Ex: If the input is 8 11 30 70 39 69 29 138 162, then the output is: 30 70 138 162 11 39 69 29 3 using namespace std; 4 5 int main() { 6 7 8 9 10 11 12 13 14 15 16 17 18 19} int numStudents; int i; cin >> numStudents; vector walkingLogs (numStudents); for (i = 0; i > walkingLogs.at(i); } * Your code goes here */ return 0; ►Code in C. Solve the code below. Write a function that takes a vector of integers, an integer n representing the number of elements in that vector, and an integer b. Implement the sequential search algorithm to look for the integer b in the vector. The sequential search works as follows: you must look at all the elements of the vector until you find the b, from the first to the last. The function must return an integer representing how many elements the function tested until it found b. If it does not find the function, it must return 0. The name of the function must be called "busca_seq". int busca_seq(int vetor[], int n, int b) { //your code } My Code #include<stdio.h> int busca_seq(int vetor[], int n, int b) { int i; for(i = 0; i < n; i++){ if(vetor[i] == b) return (i+1); } { int vet[5],n = 5,b,x; vet[0] = 1; vet[1] = 2; vet[2] = 3; vet[3] = 4; vet[4] = 5; scanf("%d",&b); x = busca_seq(vet,n,b); printf("%d",x); return 0; } }
- Finding the Minimum of a Vector Write a function to return the index of the minimum value in a vector, or -1 if the vector doesn't have any elements. In this problem you will implement the IndexOfMinimumElement function in minimum.cc and then call that function from main.cc. You do not need to edit minimum.h. Index of minimum value with std::vector Complete IndexOfMinimumElement in minimum.cc. This function takes a std::vector containing doubles as input and should return the index of the smallest value in the vector, or -1 if there are no elements. Complete main.cc Your main function asks the user how many elements they want, construct a vector, then prompts the user for each element and fills in the vector with values. Your only task in main is to call the IndexOfMinimumElement function declared in minimum.h, and print out the minimum element's index. Here's an example of how this might look: How many elements? 3 Element 0: 7 Element 1: -4 Element 2: 2 The minimum value in your…Use a range-based for loop in C++ to loop through a given vector of integers and determine how many elements in the vector are evenly divisible by either 3 or by 5. The final result should be stored in an integer variable named count. Use the following vector vec of integers (hardcoded) in your program. vector<int> vec {1,3,5,15,16,17,18,19,20,21,25,26,27,30,50,55,56,58,100,200,300,400,500,600,700}; Output: First display the integers that are evenly divisible by 3 or 5, then display the count.You have a matrix of 8x8 andbtou have to convert it into 1 d vector how can you do it. In r language