Let's consider a fixed supported beam subjected to a triangular distributed load as shown in the figure below. The equation of the bending moment(0 ≤ x ≤ 1m) is given by: X 1m Select one: OM (x) = -25 X³ + 300 X-400 (N.m) OM (x) = -25 X³ + 75 X-50 (N.m) OM (x) = -66.7 X³ + 200 X-133.3 (N.m) OM (x) = -8.3 X³ + 100 X-133.3 (N.m) M (x)=-41.7 X³ + 500 X-666.7 (N.m) 150 N/m
Let's consider a fixed supported beam subjected to a triangular distributed load as shown in the figure below. The equation of the bending moment(0 ≤ x ≤ 1m) is given by: X 1m Select one: OM (x) = -25 X³ + 300 X-400 (N.m) OM (x) = -25 X³ + 75 X-50 (N.m) OM (x) = -66.7 X³ + 200 X-133.3 (N.m) OM (x) = -8.3 X³ + 100 X-133.3 (N.m) M (x)=-41.7 X³ + 500 X-666.7 (N.m) 150 N/m
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Q6
![Let's consider a fixed supported beam subjected to a triangular distributed load as shown in the figure below. The equation of the
bending moment(0 ≤ x ≤ 1m) is given by:
X
Select one:
OM (x) = -25 X³ + 300 X-400 (N.m)
1m
OM(x) = -25 X³ +
+75 X-50 (N.m)
OM (x) = -66.7 X³ + 200 X-133.3 (N.m)
O M(x) = -8.3 X³ + 100 X-133.3 (N.m)
O M(x)=-41.7 X³ + 500 X-666.7 (N.m)
150 N/m](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F70e15475-bfd0-44c7-90b8-6640c70ea026%2Fe115bf63-fab4-405a-8b94-3fc6cdddbf3a%2Floqiii_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Let's consider a fixed supported beam subjected to a triangular distributed load as shown in the figure below. The equation of the
bending moment(0 ≤ x ≤ 1m) is given by:
X
Select one:
OM (x) = -25 X³ + 300 X-400 (N.m)
1m
OM(x) = -25 X³ +
+75 X-50 (N.m)
OM (x) = -66.7 X³ + 200 X-133.3 (N.m)
O M(x) = -8.3 X³ + 100 X-133.3 (N.m)
O M(x)=-41.7 X³ + 500 X-666.7 (N.m)
150 N/m
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