Let y(t) satisfy the following 2nd order ordinary differential equation: 4y" - 5y' - 2y = -6, with initial conditions: y(0) = -1, y'(0) = 2. Let Y(s) represent the Laplace Transform of y(t). Then Y(s) can be represented as: d N +e+fs, (4s² + bs + c)Y(s) = S where b, c, d, e and f are constants. The above equation for Y(s) may be rearranged to give: ps² + qs + r Y(s) = s(4s² + bs + c) where p, q and r are constants. Enter b: Enter c: Enter d: Enter e: Enter f: Enter p: Enter q: Enter r:

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