When the given differential equation is solved using Laplace Transform Method, the equivalent subsidiary equation with y (0) = 1 and y'(0) = - 2 S: y"+ 2y' + y = te-t O (s² + 2s + 1)y(s) = 1 + S 1 O (s² + 2s +1)y(s) = %3D (s + 1)? (s +1)? 1 1 O (s² + 2s + 1)y(s) = (s? + 2s +1) y(s) + s- 4 2. (s + 1)? (s +1)?
When the given differential equation is solved using Laplace Transform Method, the equivalent subsidiary equation with y (0) = 1 and y'(0) = - 2 S: y"+ 2y' + y = te-t O (s² + 2s + 1)y(s) = 1 + S 1 O (s² + 2s +1)y(s) = %3D (s + 1)? (s +1)? 1 1 O (s² + 2s + 1)y(s) = (s? + 2s +1) y(s) + s- 4 2. (s + 1)? (s +1)?
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question
![When the given differential equation is solved using Laplace Transform
Method, the equivalent subsidiary equation with y (0) = 1 and y'(0) = - 2
is:
y’+ 2y' + y = te-t
1
+ S
(s + 1)?
1
O (s² + 2s + 1) y(s) :
O (s² + 2s + 1)y(s) =
(s + 1)²
1
O (s? + 2s + 1)y(s) =
O (s² + 2s +1)y(s)
1
+s- 4
(s + 1)?
(s+1)?](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6b63f823-967f-4477-bbc6-0bc945bc0918%2F02f3d869-31c3-496d-9b25-27e6c5788167%2F2uhgqe8g_processed.png&w=3840&q=75)
Transcribed Image Text:When the given differential equation is solved using Laplace Transform
Method, the equivalent subsidiary equation with y (0) = 1 and y'(0) = - 2
is:
y’+ 2y' + y = te-t
1
+ S
(s + 1)?
1
O (s² + 2s + 1) y(s) :
O (s² + 2s + 1)y(s) =
(s + 1)²
1
O (s? + 2s + 1)y(s) =
O (s² + 2s +1)y(s)
1
+s- 4
(s + 1)?
(s+1)?
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