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When the given differential equation is solved using Laplace Transform Method, the equivalent subsidiary equation with y (0) = 1 and y'(0) = - 2 S: y"+ 2y' + y = te-t O (s² + 2s + 1)y(s) = 1 + S 1 O (s² + 2s +1)y(s) = %3D (s + 1)? (s +1)? 1 1 O (s² + 2s + 1)y(s) = (s? + 2s +1) y(s) + s- 4 2. (s + 1)? (s +1)?

When the given differential equation is solved using Laplace Transform Method, the equivalent subsidiary equation with y (0) = 1 and y'(0) = - 2 S: y"+ 2y' + y = te-t O (s² + 2s + 1)y(s) = 1 + S 1 O (s² + 2s +1)y(s) = %3D (s + 1)? (s +1)? 1 1 O (s² + 2s + 1)y(s) = (s? + 2s +1) y(s) + s- 4 2. (s + 1)? (s +1)?

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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When the given differential equation is solved using Laplace Transform Method, the equivalent subsidiary equation with y (0) = 1 and y'(0) = - 2 is: y’+ 2y' + y = te-t 1 + S (s + 1)? 1 O (s² + 2s + 1) y(s) : O (s² + 2s + 1)y(s) = (s + 1)² 1 O (s? + 2s + 1)y(s) = O (s² + 2s +1)y(s) 1 +s- 4 (s + 1)? (s+1)?
Transcribed Image Text:When the given differential equation is solved using Laplace Transform Method, the equivalent subsidiary equation with y (0) = 1 and y'(0) = - 2 is: y’+ 2y' + y = te-t 1 + S (s + 1)? 1 O (s² + 2s + 1) y(s) : O (s² + 2s + 1)y(s) = (s + 1)² 1 O (s? + 2s + 1)y(s) = O (s² + 2s +1)y(s) 1 +s- 4 (s + 1)? (s+1)?
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