Consider the differential equation y"-y'-2y=e' conditions y(0) = 8, y'(0)=0. with initial What function y(s) is obtained by solving using the square transform 8 (s-1+1 Y(s)- (s-1)(s-2)(s+1) 8(s-1)+1 (s-2)(s+1)(s-1) b. y(s)= 8 (s+1)2+1 (s-2)(s+1)(s- 1) Y(s)= - 8 (s-1) (s-2)(s+1)(s-1) d. Y(s)=

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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Consider the differential equation y"-y'-2y=e' with initial
conditions y(0) = 8, y'(0)=0.
What function y(s) is obtained by solving using the square
transform
8 (s-1)7+1
(s-1)(s-2)(s+1)
a. y(s)
8(s-1)+1
(s-2)(s+1)(s- 1)
b.
Y(s) =
8 (s+1)2+1
(s-2)(s+1)(s-1)
Y(s) =
d. y(s)=
8 (s-1)
(s-2)(s+1)(s - 1)
Transcribed Image Text:Consider the differential equation y"-y'-2y=e' with initial conditions y(0) = 8, y'(0)=0. What function y(s) is obtained by solving using the square transform 8 (s-1)7+1 (s-1)(s-2)(s+1) a. y(s) 8(s-1)+1 (s-2)(s+1)(s- 1) b. Y(s) = 8 (s+1)2+1 (s-2)(s+1)(s-1) Y(s) = d. y(s)= 8 (s-1) (s-2)(s+1)(s - 1)
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