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y" + 2y' + y = te-t (s² + 2s + 1) y(s) 1 1)y(s) = (s² 1 + 2s + 1) y(s) = (s + 1)? (s + 1)* A.) В.) 1 1 (s? + 2s + 1) y(s) = (s² + 2s +1) y(s) : s- 4 (s+1)? (s + 1)² C.) D.)

y" + 2y' + y = te-t (s² + 2s + 1) y(s) 1 1)y(s) = (s² 1 + 2s + 1) y(s) = (s + 1)? (s + 1)* A.) В.) 1 1 (s? + 2s + 1) y(s) = (s² + 2s +1) y(s) : s- 4 (s+1)? (s + 1)² C.) D.)

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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When the given differential equation is solved using Laplace Transform Method, the equivalent subsidiary equation with y (0) = 1 and y’(0) = - 2 is

y"+ 2y' + y = te-t 1 (s? + 2s +1) y(s) = 1 + s (s + 1)? (s² + 2s + 1) y(s) (s + 1)? O A.) O B.) 1 (s? + 2s + 1) y(s) = 1 -+ s - 4 (s + 1)? (s? + 2s +1) y(s) = (s + 1)? O D.)
Transcribed Image Text:y"+ 2y' + y = te-t 1 (s? + 2s +1) y(s) = 1 + s (s + 1)? (s² + 2s + 1) y(s) (s + 1)? O A.) O B.) 1 (s? + 2s + 1) y(s) = 1 -+ s - 4 (s + 1)? (s? + 2s +1) y(s) = (s + 1)? O D.)
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