Let y be the solution of the initial value problem - ´y" — 2 y' – 3 y = 0 \y(0) = 1, y'(0) = 1 Then y' (In(2)) − y(In(2)) = - y' (In(2)) − y(In(2)) = 15 2 15 = 32 3 y' (In(2)) − y(In(2)) = 16 y' (In(2)) − y(In(2)) - = 15 8 3 y' (In(2)) − y(In(2)) = = 32 Which of the following is a solution of the differential equation y"" +8y = 0? Select all that apply. y = -3t et (3 cos(√3 (t+1) ) + 2 e²−3 ) y = 3 e−2 (t+2) + 5 e²+1 sin (√3t) ☐ y = 2 et + cos cos (√3 t) -2 t y = (2 cos (√3t) + 3 sin (√3t) - 5 et ☐ y = 3 cos(√3t) - 2 sin(√3t) У = et ( 2 cos (√√3 t) + 3 sin (√3 t) - 5 e-³t e-³)
Let y be the solution of the initial value problem - ´y" — 2 y' – 3 y = 0 \y(0) = 1, y'(0) = 1 Then y' (In(2)) − y(In(2)) = - y' (In(2)) − y(In(2)) = 15 2 15 = 32 3 y' (In(2)) − y(In(2)) = 16 y' (In(2)) − y(In(2)) - = 15 8 3 y' (In(2)) − y(In(2)) = = 32 Which of the following is a solution of the differential equation y"" +8y = 0? Select all that apply. y = -3t et (3 cos(√3 (t+1) ) + 2 e²−3 ) y = 3 e−2 (t+2) + 5 e²+1 sin (√3t) ☐ y = 2 et + cos cos (√3 t) -2 t y = (2 cos (√3t) + 3 sin (√3t) - 5 et ☐ y = 3 cos(√3t) - 2 sin(√3t) У = et ( 2 cos (√√3 t) + 3 sin (√3 t) - 5 e-³t e-³)
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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