Which of the following is a solution of the differential equation y″ – 64 y = 0? Select all that apply. y = 2 e²t + cos (2√3 t ) y = 3 cos (2√3 t) - 2 sin (2√3t) -2t = e (2 cos(2√3t) y = e4 У = y = +3 2v + 3 sin sin (2√3 t) - 5 e6t ) * (2 cos (2√3t) + 3 sin sin (2√3t) - 5 e-2t) t) 3 e4(+2)+5e −2(t+1) sin (2√3 1 -2t e ( 3 cos (2√3 (t+1)) + 2e6+3 ) Let y be the solution of the initial value problem fy"+6y+5y=0 {y(0) = 1, y'(0) = -3 Then y' (In(2)) + 3y(In(2)) y' (In(2)) + 3y (In(2)) y' (In(2)) + 3y (In(2)) y' (In(2)) + 3y(ln(2)) y' (In(2)) + 3y(ln(2)) 3 = 32 15 = 8 3 = 16 15 = 2 15 = 32