Deduce the estimators for the paparmeters of normally distributed poulation using Maximum Liklihood(Please solve in clear handwriting) Let X₁, ..., Xpthe pdf isx₁ be a random sample from a normal distribution N(µ,σ²)SOƒ (x | 14₂ 0²³) = √ √ √ 27° (x-µ)²1= exp{-20²with vector parametr (µ,0²)➤ The likelihood function isL(µ‚0²) = ƒ (x,,...,x„; µ‚0²) = Ï] [-i=1=In[ƒ(x₁, . . . , x₁; µ, σ²)]1συ2πn11(0√27) "exp(-20²2 Σ (x-μ)²}=)"i=1=2(x₁exp{-(x-μ)²}]20²In (2πσ²)120²Σ(x; -μ)²

Given Xi~N(population mean μ, standard deviations σ); i=1,2,...,n

Answered: ➤ Let X₁,. the pdf is , Xn „be a random…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

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Section: Chapter Questions

Problem 1P

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Deduce the estimators for the paparmeters of normally distributed poulation using Maximum Liklihood

(Please solve in clear handwriting)

Let X₁, ..., Xp
the pdf is
x₁ be a random sample from a normal distribution N(µ,σ²)
SO
ƒ (x | 14₂ 0²³) = √ √ √ 27° (x-µ)²
1
= exp{-
20²
with vector parametr (µ,0²)
➤ The likelihood function is
L(µ‚0²) = ƒ (x,,...,x„; µ‚0²) = Ï] [-
i=1
=
In[ƒ(x₁, . . . , x₁; µ, σ²)]
1
συ2π
n
1
1
(0√27) "exp(-20²2 Σ (x-μ)²}
=)"
i=1
=
2
(x₁
exp{-(x-μ)²}]
20²
In (2πσ²)
1
20²
Σ(x; -μ)²

Features Features Normal distribution is characterized by two parameters, mean (µ) and standard deviation (σ). When graphed, the mean represents the center of the bell curve and the graph is perfectly symmetric about the center. The mean, median, and mode are all equal for a normal distribution. The standard deviation measures the data's spread from the center. The higher the standard deviation, the more the data is spread out and the flatter the bell curve looks. Variance is another commonly used measure of the spread of the distribution and is equal to the square of the standard deviation.

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