Please solve the blanks in (b) and (c) and show your work/explain the steps, thanks!! The calibration of a scale is to be checked by weighing a 11 kg test specimen 25 times. Suppose that the results of different weighings are independent of one another and that the weight on each trial is normally distributed with o = 0.200 kg. Let u denote the true average weight reading on the scale.(a) What hypotheses should be tested?O Ho: H = 11H: 4 > 11O Hoi H = 11H: H # 11O Hoi H = 11H3: H < 11O Ho: H+ 11H3 H = 11O Hoi H* 11H: H < 11(b) With the sample mean itself as the test statistic, what is the P-value when x = 10.81? (Round your answer to four decimal places.)What would you conclude at significance level 0.01?O Conclude that the true mean measured weight is the same as 11 kg.Conclude that the true mean measured weight differs from 11 kg.(c) For a test with a = 0.01, what is the probability that recalibration is judged unnecessary when in fact u = 11.2? (Round your answer to four decimal places.)For a test with a = 0.01, what is the probability that recalibration is judged unnecessary when in fact u = 10.9? (Round your answer to four decimal places.)

The calibration of a scale is to be checked by weighing a 11 kg test specimen 25 times. Suppose that the results of different weighings are independent of one another and that the weight on each trial is normally distributed with o- 0.200 kg. Let u denote the true average vweight reading on the scal (a) What hypotheses should be tested? O Hol H= 11 H,i H> 11 O Hoi H= 11 H, * 11 O Hoi H = 11 H H< 11 O Họi H* 11 H= 11 O Hoi H* 11 (b) With the sample mean itself as the test statistic, vhat is the P-value when x = 10.817 (Round your answer to four decimal places.) What would you conclude at significance level 0.01? O Conclude that the true mean measured weight is the same as 11 kg. O Conclude that the true mean measured weight differs from 11 kg.

The calibration of a scale is to be checked by weighing a 11 kg test specimen 25 times. Suppose that the results of different weighings are independent of one another and that the weight on each trial is normally distributed with o- 0.200 kg. Let u denote the true average vweight reading on the scal (a) What hypotheses should be tested? O Hol H= 11 H,i H> 11 O Hoi H= 11 H, * 11 O Hoi H = 11 H H< 11 O Họi H* 11 H= 11 O Hoi H* 11 (b) With the sample mean itself as the test statistic, vhat is the P-value when x = 10.817 (Round your answer to four decimal places.) What would you conclude at significance level 0.01? O Conclude that the true mean measured weight is the same as 11 kg. O Conclude that the true mean measured weight differs from 11 kg.

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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Please solve the blanks in (b) and (c) and show your work/explain the steps, thanks!!

The calibration of a scale is to be checked by weighing a 11 kg test specimen 25 times. Suppose that the results of different weighings are independent of one another and that the weight on each trial is normally distributed with o = 0.200 kg. Let u denote the true average weight reading on the scale.
(a) What hypotheses should be tested?
O Ho: H = 11
H: 4 > 11
O Hoi H = 11
H: H # 11
O Hoi H = 11
H3: H < 11
O Ho: H+ 11
H3 H = 11
O Hoi H* 11
H: H < 11
(b) With the sample mean itself as the test statistic, what is the P-value when x = 10.81? (Round your answer to four decimal places.)
What would you conclude at significance level 0.01?
O Conclude that the true mean measured weight is the same as 11 kg.
Conclude that the true mean measured weight differs from 11 kg.
(c) For a test with a = 0.01, what is the probability that recalibration is judged unnecessary when in fact u = 11.2? (Round your answer to four decimal places.)
For a test with a = 0.01, what is the probability that recalibration is judged unnecessary when in fact u = 10.9? (Round your answer to four decimal places.)

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