Let X represent the full height of a certain species of tree. Assume that X has a normal probability distribution with μ = 248.8 ft and σ = 5.1 ft. You intend to measure a random sample of n = 241 trees. a. What is the mean of the distribution of sample means? f = ft b. What is the standard deviation of the distribution of sample means (i.e., the standard error in estimating the mean)? σ = ft c. What is the probability that the average height of a random sample of 241 trees is larger than 249? Round answer to 4 decimal places. P(x > 249) =

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Let X represent the full height of a certain species of tree. Assume that X has a normal probability
distribution with μ = 248.8 ft and o = 5.1 ft.
You intend to measure a random sample of n =
a. What is the mean of the distribution of sample means?
Hã
ft
=
b. What is the standard deviation of the distribution of sample means (i.e., the standard error in
estimating the mean)?
0x =
241 trees.
P(x > 249)
ft
c. What is the probability that the average height of a random sample of 241 trees is larger than 249?
Round answer to 4 decimal places.
=
Transcribed Image Text:Let X represent the full height of a certain species of tree. Assume that X has a normal probability distribution with μ = 248.8 ft and o = 5.1 ft. You intend to measure a random sample of n = a. What is the mean of the distribution of sample means? Hã ft = b. What is the standard deviation of the distribution of sample means (i.e., the standard error in estimating the mean)? 0x = 241 trees. P(x > 249) ft c. What is the probability that the average height of a random sample of 241 trees is larger than 249? Round answer to 4 decimal places. =
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