Let us use the list [d1, d2, represent the (positive) big-integer d1d2...dn. type BigInt = [Int] dn], where each di is between 0 and 9, to For example, [9, 9, 9, 9, 9, 9, 9, 9, 9, 8] represents the big-integer 9999999998. Fill out the implementation for bigAdd :: BigInt -> BigInt -> BigInt so that it takes two integer lists, where each integer is between 0 and 9 and returns the list corresponding to the addition of the two big-integers. Again, you have to fill in the implementation to supply the appropriate values to f, base, args. You should get the following behavior: ghci> bigAdd [9, 9] [1, 0, 0, 2] [1, 1, 0, 1] ghci> bigAdd [9, 9, 9, 9] [9, 9, 9] [1, 0, 9, 9, 8]

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
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```haskell
----------------------------------------------------------------------
-- | `mulByInt i n` returns the result of multiplying
--   the int `i` with `BigInt` `n`.
--
-- >>> mulByInt 9 [9,9,9,9]
-- [8,9,9,9,1]
----------------------------------------------------------------------

mulByInt :: Int -> BigInt -> BigInt
mulByInt i n = error "TBD:mulByInt"
```

### Explanation:

This Haskell code snippet defines the type signature and concept for a function called `mulByInt`.

- **Function Purpose**: The function `mulByInt` is designed to multiply an integer `i` by a `BigInt` `n`. A `BigInt` is typically a large integer stored in an array format.
  
- **Example Execution**: The example `mulByInt 9 [9,9,9,9]` demonstrates multiplying the integer `9` by the `BigInt` representation `[9,9,9,9]`, which yields the result `[8,9,9,9,1]`.

- **Type Signature**: `mulByInt :: Int -> BigInt -> BigInt`, indicates that `mulByInt` takes an integer and a `BigInt` as input and returns a `BigInt`.

- **Implementation Note**: The function currently uses `error "TBD:mulByInt"`, indicating that the actual implementation is yet to be defined (TBD stands for "To Be Done").
Transcribed Image Text:```haskell ---------------------------------------------------------------------- -- | `mulByInt i n` returns the result of multiplying -- the int `i` with `BigInt` `n`. -- -- >>> mulByInt 9 [9,9,9,9] -- [8,9,9,9,1] ---------------------------------------------------------------------- mulByInt :: Int -> BigInt -> BigInt mulByInt i n = error "TBD:mulByInt" ``` ### Explanation: This Haskell code snippet defines the type signature and concept for a function called `mulByInt`. - **Function Purpose**: The function `mulByInt` is designed to multiply an integer `i` by a `BigInt` `n`. A `BigInt` is typically a large integer stored in an array format. - **Example Execution**: The example `mulByInt 9 [9,9,9,9]` demonstrates multiplying the integer `9` by the `BigInt` representation `[9,9,9,9]`, which yields the result `[8,9,9,9,1]`. - **Type Signature**: `mulByInt :: Int -> BigInt -> BigInt`, indicates that `mulByInt` takes an integer and a `BigInt` as input and returns a `BigInt`. - **Implementation Note**: The function currently uses `error "TBD:mulByInt"`, indicating that the actual implementation is yet to be defined (TBD stands for "To Be Done").
### Introduction to Big Integer Representation with Haskell

In this lesson, we explore how to represent and manipulate large integers using lists in Haskell.

#### Big-Integer Representation

We use a list `[d1, d2, ..., dn]` where each element `di` is a digit between `0` and `9`, to represent the positive big-integer `d1d2...dn`.

```haskell
type BigInt = [Int]
```

#### Example

The list `[9, 9, 9, 9, 9, 9, 9, 9, 9, 8]` represents the big-integer `9999999998`. Your task is to implement the function:

```haskell
bigAdd :: BigInt -> BigInt -> BigInt
```

This function should take two integer lists (each integer being between `0` and `9`) and return a list representing the sum of the two big-integers. This involves completing the implementation to provide appropriate values to `f`, `base`, and `args`.

#### Desired Behavior

The function should exhibit the following behavior:

```haskell
ghci> bigAdd [9, 9] [1, 0, 0, 2]
[1, 1, 0, 1]

ghci> bigAdd [9, 9, 9, 9] [9, 9]
[1, 0, 9, 9, 8]
```

By mastering the manipulation of these lists, you'll be able to handle computations involving large numbers efficiently in Haskell.
Transcribed Image Text:### Introduction to Big Integer Representation with Haskell In this lesson, we explore how to represent and manipulate large integers using lists in Haskell. #### Big-Integer Representation We use a list `[d1, d2, ..., dn]` where each element `di` is a digit between `0` and `9`, to represent the positive big-integer `d1d2...dn`. ```haskell type BigInt = [Int] ``` #### Example The list `[9, 9, 9, 9, 9, 9, 9, 9, 9, 8]` represents the big-integer `9999999998`. Your task is to implement the function: ```haskell bigAdd :: BigInt -> BigInt -> BigInt ``` This function should take two integer lists (each integer being between `0` and `9`) and return a list representing the sum of the two big-integers. This involves completing the implementation to provide appropriate values to `f`, `base`, and `args`. #### Desired Behavior The function should exhibit the following behavior: ```haskell ghci> bigAdd [9, 9] [1, 0, 0, 2] [1, 1, 0, 1] ghci> bigAdd [9, 9, 9, 9] [9, 9] [1, 0, 9, 9, 8] ``` By mastering the manipulation of these lists, you'll be able to handle computations involving large numbers efficiently in Haskell.
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