Let us now recall that the energy of a capacitor can be thought of as the energy of the electric field inside the capacitor. The energy of the electric field is usually described in terms of energy density u, the energy per unit volume. A parallel-plate capacitor is a convenient device for obtaining the formula for the energy density of an electric field, since the electric field inside it is nearly uniform. The formula for energy density can then be written as u = 음, where U is the energy of the capacitor and V is the volume of the capacitor (not its voltage). Part F A parallel-plate capacitor has area A and plate separation d, and it is charged so that the electric field inside is Ę. Use the formulas from the problem introduction to find the energy U of the capacitor. Express your answer in terms of A, d, E, and appropriate constants.

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Find the energy density u of the electric field in a parallel-plate
capacitor. The magnitude of the electric field inside the capacitor is E.
Express your answer in terms of E and appropriate constants.
View Available Hint(s)
ΜΕ ΑΣΦ
0
?
E²
u =
1
2
e
Submit
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Transcribed Image Text:Find the energy density u of the electric field in a parallel-plate capacitor. The magnitude of the electric field inside the capacitor is E. Express your answer in terms of E and appropriate constants. View Available Hint(s) ΜΕ ΑΣΦ 0 ? E² u = 1 2 e Submit Previous Answers × Incorrect; Try Again; 5 attempts remaining
Let us now recall that the energy of a capacitor can be thought of as the
energy of the electric field inside the capacitor. The energy of the electric
field is usually described in terms of energy density u, the energy per unit
volume.
A parallel-plate capacitor is a convenient device for obtaining the formula
for the energy density of an electric field, since the electric field inside it is
nearly uniform. The formula for energy density can then be written as
U
u =
V'
where U is the energy of the capacitor and V is the volume of the
capacitor (not its voltage).
Part F
A parallel-plate capacitor has area A and plate separation d, and it is
charged so that the electric field inside is Ę. Use the formulas from the
problem introduction to find the energy U of the capacitor.
Express your answer in terms of A, d, E, and appropriate
constants.
▸ View Available Hint(s)
U
=
ΤΙ ΑΣΦ
?
Transcribed Image Text:Let us now recall that the energy of a capacitor can be thought of as the energy of the electric field inside the capacitor. The energy of the electric field is usually described in terms of energy density u, the energy per unit volume. A parallel-plate capacitor is a convenient device for obtaining the formula for the energy density of an electric field, since the electric field inside it is nearly uniform. The formula for energy density can then be written as U u = V' where U is the energy of the capacitor and V is the volume of the capacitor (not its voltage). Part F A parallel-plate capacitor has area A and plate separation d, and it is charged so that the electric field inside is Ę. Use the formulas from the problem introduction to find the energy U of the capacitor. Express your answer in terms of A, d, E, and appropriate constants. ▸ View Available Hint(s) U = ΤΙ ΑΣΦ ?
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