**Question 3: Capacitor Configuration Exercise**Four capacitors are arranged in the following configuration. The capacitances of the capacitors are:- \(C_1 = 3.0 \, \mu \text{F}\)- \(C_2 = 2.0 \, \mu \text{F}\)- \(C_3 = 1.8 \, \mu \text{F}\)- \(C_4 = 3.0 \, \mu \text{F}\)The battery voltage is \(12.0 \, \text{V}\).**Tasks:**(a) Calculate the equivalent capacitance of the configuration.(b) Determine how much energy is stored in this capacitor configuration.(c) Calculate how much energy is stored in capacitor \(C_1\).**Diagram Explanation:**The diagram shows four capacitors arranged in a combination of series and parallel connections.- \(C_4\) is connected in series with the parallel combination of \(C_2\) and the series arrangement of \(C_3\) and \(C_1\).- \(C_2\) is connected in parallel with the series line connecting \(C_3\) and \(C_1\).- \(V\) represents the battery voltage applied across the entire network.This layout necessitates using the rules for both series and parallel arrangements to compute the equivalent capacitance and energy stored.

Given, c1=3μF=3×10-6Fc2=2μF=2×10-6Fc3=1.8μF=1.8×10-6Fc4=3μF=3×10-6F (a) The diagram shows that c2…

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