Let u₁5 2 4₂ -1 0 and u3 = 0. Note that u₁ and u₂ are orthogonal but that u3 is not orthogonal to u₁ or u₂. It can be shown that u3 is not in the subspace W spanned by u₁ and u₂. Use this fact to construct a nonzero vector v in R³ that is orthogonal to u₁ and ₂. A nonzero vector in R³ that is orthogonal to u₁ and u₂ is v=

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Q: (d) Consider the following system of linear equations 2x1 – 3x2 + x3 - 3x4 + 2x5 = 6 2x1 – 3x2 + 5x3…

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