Let f(x) be a function that has a Taylor Series centred at x = 3 given by converges. What is the smallest value of k for which the derivative f(*) (4) # 0? k = What is the value of this derivative? ƒ(*) (4) = f(x) = DO 3n² (2n + 1)! -(x-4)²n+2

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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Let f(x) be a function that has a Taylor Series centred at x =
converges.
= 3 given by
What is the smallest value of k for which the derivative f(*) (4) ‡ 0? k =
What is the value of this derivative? (*) (4) =
f(x) =_3"n²
(2n+1)! (-4)²n+2
Transcribed Image Text:Let f(x) be a function that has a Taylor Series centred at x = converges. = 3 given by What is the smallest value of k for which the derivative f(*) (4) ‡ 0? k = What is the value of this derivative? (*) (4) = f(x) =_3"n² (2n+1)! (-4)²n+2
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