Find the 3rd degree Maclaurin Polynomial for f(x) = 2". d -b² = In(b) · b². dx Recall that T3(x) Then the Maclaurin series for f(x) = 2" is: T(x) = £ n=0 Your answer may disappear. The bug has been reported and is being worked on. And this series converges on the interval: enter answer in interval notation. Use oo for oo.

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