: Let f [a, b] → R be a bounded function. Then f : [a, b] → R is Riemann integrable if and only if there is a sequence {Pn} of partitions of [a, b] such that lim (U(f, Pn) - L(f, Pn)) = 0. n1x In this case, the Riemann integral of f over [a, b] can be computed by S ["¹= f = lim L(f, Pn) = lim U(f, Pn). n1x n→∞ a (4.1) (4.2)

Elements Of Modern Algebra
8th Edition
ISBN:9781285463230
Author:Gilbert, Linda, Jimmie
Publisher:Gilbert, Linda, Jimmie
Chapter5: Rings, Integral Domains, And Fields
Section5.2: Integral Domains And Fields
Problem 21E: [Type here] 21. Prove that ifand are integral domains, then the direct sum is not an integral...
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Let f [a, b] → R be a bounded function. Then f [a, b] → R is Riemann
!
integrable if and only if there is a sequence {Pn} of partitions of [a, b] such
that
lim (U(f, Pn) L(f, Pn)) = 0.
(4.1)
n→∞
In this case, the Riemann integral of f over [a, b] can be computed by
a
1
= lim L(f, Pn)
n-x
=
lim U(f, Pn).
n→∞
(4.2)
Transcribed Image Text:Let f [a, b] → R be a bounded function. Then f [a, b] → R is Riemann ! integrable if and only if there is a sequence {Pn} of partitions of [a, b] such that lim (U(f, Pn) L(f, Pn)) = 0. (4.1) n→∞ In this case, the Riemann integral of f over [a, b] can be computed by a 1 = lim L(f, Pn) n-x = lim U(f, Pn). n→∞ (4.2)
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