Suppose a random sample of size 49 is selected from a population with = 11. Find the value of the standard error of the mean in each of the following cases (use the finite population correction factor if appropriate). a. The population size is infinite (to 2 decimals). 1.57 b. The population size is N = 50,000 (to 2 decimals). 1.57 c. The population size is N = 5000 (to 2 decimals). 1.56 d. The population size is N = 500 (to 2 decimals).

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.5: Comparing Sets Of Data
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**Standard Error of the Mean Calculation**

Suppose a random sample of size 49 is selected from a population with a standard deviation (\(\sigma\)) of 11. Find the value of the standard error of the mean in each of the following cases (use the finite population correction factor if appropriate).

**a. The population size is infinite (to 2 decimals).**
- Standard Error: 1.57

**b. The population size is \(N = 50{,}000\) (to 2 decimals).**
- Standard Error: 1.57

**c. The population size is \(N = 5{,}000\) (to 2 decimals).**
- Standard Error: 1.56

**d. The population size is \(N = 500\) (to 2 decimals).**
- Standard Error: [Not provided]

The standard error is calculated using the formula:

\[
SE = \frac{\sigma}{\sqrt{n}}
\]

Where \(SE\) is the standard error, \(\sigma\) is the population standard deviation, and \(n\) is the sample size. When the population is finite, the finite population correction (FPC) factor is applied:

\[
SE_{finite} = SE \times \sqrt{\frac{N-n}{N-1}}
\]

Where \(N\) is the population size.
Transcribed Image Text:**Standard Error of the Mean Calculation** Suppose a random sample of size 49 is selected from a population with a standard deviation (\(\sigma\)) of 11. Find the value of the standard error of the mean in each of the following cases (use the finite population correction factor if appropriate). **a. The population size is infinite (to 2 decimals).** - Standard Error: 1.57 **b. The population size is \(N = 50{,}000\) (to 2 decimals).** - Standard Error: 1.57 **c. The population size is \(N = 5{,}000\) (to 2 decimals).** - Standard Error: 1.56 **d. The population size is \(N = 500\) (to 2 decimals).** - Standard Error: [Not provided] The standard error is calculated using the formula: \[ SE = \frac{\sigma}{\sqrt{n}} \] Where \(SE\) is the standard error, \(\sigma\) is the population standard deviation, and \(n\) is the sample size. When the population is finite, the finite population correction (FPC) factor is applied: \[ SE_{finite} = SE \times \sqrt{\frac{N-n}{N-1}} \] Where \(N\) is the population size.
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