Let a parallel plate capacitor be in vacuum with one plate (cathode) located at x = 0 emitting electrons which are collected at the other plate (anode) located at x = d.The arrangement makes up a vacuum diode. Let the volume charge density within the capacitor be given by Iv(x) = -(4/9) eo Vo d-4/3 x 2/3 C/m³ where the cathode is located at x = 0 and the anode at x = d. The voltage between the anode and the cathode is Vo and the total charge in 1 m² cross section is -21 nC. 1. Find the Vo if d = 2 mm. 2. Find d if Vo = 5 V. (5 pts) (5 pts) nt: You are given the total charge, so all you need to do is to integrate the volume charge density er the volume in cartesian coordinates which will be dv = 1 m² dx and you will obtain an equation ich you can solve for either Voor d.

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Let a parallel plate capacitor be in vacuum with one plate (cathode) located at x = 0
emitting electrons which are collected at the other plate (anode) located at x = d.The
arrangement makes up a vacuum diode.
Let the volume charge density within the capacitor be given by
ry(x) = -(4/9) eo Vo d-4/3 x 2/3 C/m³
where the cathode is located at x = 0 and the anode at x = d.
The voltage between the anode and the cathode is Vo and the total charge in 1 m²
cross section is -21 nC.
1. Find the Vo if d = 2 mm.
2. Find d if Vo = 5 V.
(5 pts)
(5 pts)
Hint: You are given the total charge, so all you need to do is to integrate the volume charge density
over the volume in cartesian coordinates which will be dv = 1 m² dx and you will obtain an equation
which you can solve for either V₁ or d.
Transcribed Image Text:Let a parallel plate capacitor be in vacuum with one plate (cathode) located at x = 0 emitting electrons which are collected at the other plate (anode) located at x = d.The arrangement makes up a vacuum diode. Let the volume charge density within the capacitor be given by ry(x) = -(4/9) eo Vo d-4/3 x 2/3 C/m³ where the cathode is located at x = 0 and the anode at x = d. The voltage between the anode and the cathode is Vo and the total charge in 1 m² cross section is -21 nC. 1. Find the Vo if d = 2 mm. 2. Find d if Vo = 5 V. (5 pts) (5 pts) Hint: You are given the total charge, so all you need to do is to integrate the volume charge density over the volume in cartesian coordinates which will be dv = 1 m² dx and you will obtain an equation which you can solve for either V₁ or d.
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