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Introductory Circuit Analysis (13th Edition)

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Question

Two positive point charges q1=4.40 uC and q2=6.40 uC are separated in vaccum in distacne of 6.0m find the magnitude of the net electric at point r!=4.80m from q1 in N/C

Expert Solution

Step 1

Given data is -

$\begin{array}{rcl} Charge q_{1} & = & 4.4 μc \\ q_{2} & = & 6.40 μc \\ Distance & = & 6.0 m \\ Point r & = & 4.80 m \\ Electric field E & = & k \frac{q}{r^{2}} \end{array}$

Step 2

So electric field due to $q_{1}$ .

$\begin{array}{rcl} r & = & \sqrt{{(6)}^{2} + {(4.80)}^{2}} \\ r & = & \sqrt{59.04} \\ r & = & 7.6 m \\ E_{1} & = & k \frac{q_{1}}{r^{2}} \\ k & = & 9 \times 10^{9} {Nm}^{2} / C = constant \\ E_{1} & = & \frac{8.99 \times 10^{9} \times 4.4 \times 10^{- 6}}{{(7.6)}^{2}} \\ E_{1} & = & 684.83 N/C \end{array}$

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