Let 3nvs-2n3+n Wn 6n5+2n2 Y = 3n2(2n3 + 1)' - 1 2nn and Z, =1- sin %3D 6nvi + 4n3 -8 Note: Here the main problem is finding the explicit limit. O A. The sequences W and Y converge to oo and 1, respectively while Z diverges O B. The sequences Wn and Y converge to 0 and oo, respectively while Zn converges to 1 O C. The sequences W and Y, converge to 0 and 6, respectively while Z, converges to 1/2. O D. The sequences Wn and Y, converge to -1/2 and oo, respectively while Z, converges to 0. O E. The sequences W and Y converge to 1/2 and 0, respectively while Z, diverges O F. The sequences W and Y converge to -1/2, and 1, respectively while Z diverges

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