les of LIOH Would be required to completely neutralize 6.0 H2CO3 + 2LIOH 2H20 + LizCO3

Chemistry
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**Chemistry Question: Neutralization Reaction Calculation**

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**Question:**

According to the following reaction, how many moles of LiOH would be required to completely neutralize 6.0 moles of H₂CO₃?

\[ \text{H}_2\text{CO}_3 + 2\text{LiOH} \rightarrow 2\text{H}_2\text{O} + \text{Li}_2\text{CO}_3 \]

Your answer should be rounded to one decimal place. Enter your answer as a number without units.

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**Explanation of Reaction:**

The given reaction is a neutralization reaction where lithium hydroxide (LiOH) reacts with carbonic acid (H₂CO₃) to produce water (H₂O) and lithium carbonate (Li₂CO₃).

Based on the balanced chemical equation, one mole of H₂CO₃ requires 2 moles of LiOH to be completely neutralized.

To determine how many moles of LiOH are needed to neutralize 6.0 moles of H₂CO₃, we use the stoichiometric ratio from the equation:

1 mole of H₂CO₃ : 2 moles of LiOH

Therefore, for 6.0 moles of H₂CO₃, the required moles of LiOH would be:

6.0 moles of H₂CO₃ * 2 = 12.0 moles of LiOH

Instruction to the Student:

Enter your answer as **12.0** without including any units.
Transcribed Image Text:**Chemistry Question: Neutralization Reaction Calculation** --- **Question:** According to the following reaction, how many moles of LiOH would be required to completely neutralize 6.0 moles of H₂CO₃? \[ \text{H}_2\text{CO}_3 + 2\text{LiOH} \rightarrow 2\text{H}_2\text{O} + \text{Li}_2\text{CO}_3 \] Your answer should be rounded to one decimal place. Enter your answer as a number without units. --- **Explanation of Reaction:** The given reaction is a neutralization reaction where lithium hydroxide (LiOH) reacts with carbonic acid (H₂CO₃) to produce water (H₂O) and lithium carbonate (Li₂CO₃). Based on the balanced chemical equation, one mole of H₂CO₃ requires 2 moles of LiOH to be completely neutralized. To determine how many moles of LiOH are needed to neutralize 6.0 moles of H₂CO₃, we use the stoichiometric ratio from the equation: 1 mole of H₂CO₃ : 2 moles of LiOH Therefore, for 6.0 moles of H₂CO₃, the required moles of LiOH would be: 6.0 moles of H₂CO₃ * 2 = 12.0 moles of LiOH Instruction to the Student: Enter your answer as **12.0** without including any units.
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