length `length` and 'K factor' = `k_factor` which belong to the criteria represented by that index:     - dp[length][k_factor][0] can be the number of strings of length `length`       and K-factor = `k_factor` which end with substring 'a'     - dp[length][k_factor][1] can be the number of strings of length `length`       and K-factor = `k_factor` which end with substring 'ab'     - dp[length][k_factor][2] can be the number of strings of length `length`       and K-factor = `k_factor` which end with subs

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Code!!!!!!'
The K factor of a string is defined as the number of times 'abba' appears as a
substring. Given two numbers `length` and `k_factor`, find the number of
strings of length `length` with 'K factor' = `k_factor`.

The algorithms is as follows:

dp[length][k_factor] will be a 4 element array, wherein each element can be the
number of strings of length `length` and 'K factor' = `k_factor` which belong
to the criteria represented by that index:

    - dp[length][k_factor][0] can be the number of strings of length `length`
      and K-factor = `k_factor` which end with substring 'a'

    - dp[length][k_factor][1] can be the number of strings of length `length`
      and K-factor = `k_factor` which end with substring 'ab'

    - dp[length][k_factor][2] can be the number of strings of length `length`
      and K-factor = `k_factor` which end with substring 'abb'

    - dp[length][k_factor][3] can be the number of strings of `length` and
      K-factor = `k_factor` which end with anything other than the above
      substrings (anything other than 'a' 'ab' 'abb')

Example inputs

length=4 k_factor=1  no of strings = 1
length=7 k_factor=1 no of strings = 70302
length=10 k_factor=2 no of strings = 74357.

No chatgp. 

 

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