For the second picture Can you fix the loop for the algorithm in python class Solution:def majorityElement (self, nums: List[int]) -> int:2if len(nums) % 2 == 1:count = nums.count(nums [0])if count > len(nums) // 2:return nums[0]else:356.78nums.pop(0)temp = []for i in range(0, len(nums), 2):if nums[i] == nums[i + 1]:1011 -12temp.append(nums [i])x = self.majorityElement(temp)if nums.count(x) > len(nums) // 2:131415return x16else:17return False ull T-Mobile11:21 PM22%E LeetCode* Pick OneGiven an array nums of size n, return the majorityelement.The majority element is the element that appearsmore than [n / 2] times. You may assume thatthe majority element always exists in the array.Example 1:Input: nums =[3,2,3]Output: 3Example 2:Input: nums =Output: 2[2,2,1,1,1,2,2]AAleetcode.com

PROGRAM INTRODUCTION: Start the definition of the function to find the majority element from the…

Given an array nums of size n, return the majority element. The majority element is the element that appears more than [n / 2] times. You may assume that the majority element always exists in the array. Example 1: Input: nums = [3,2,3] Output: 3 Example 2: Input: nums = Output: 2 [2,2,1,1,1,2,2] %3D

Given an array nums of size n, return the majority element. The majority element is the element that appears more than [n / 2] times. You may assume that the majority element always exists in the array. Example 1: Input: nums = [3,2,3] Output: 3 Example 2: Input: nums = Output: 2 [2,2,1,1,1,2,2] %3D

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

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Question

For the second picture Can you fix the loop for the algorithm in python

class Solution:
def majorityElement (self, nums: List[int]) -> int:
2
if len(nums) % 2 == 1:
count = nums.count(nums [0])
if count > len(nums) // 2:
return nums[0]
else:
3
5
6.
7
8
nums.pop(0)
temp = []
for i in range(0, len(nums), 2):
if nums[i] == nums[i + 1]:
10
11 -
12
temp.append(nums [i])
x = self.majorityElement(temp)
if nums.count(x) > len(nums) // 2:
13
14
15
return x
16
else:
17
return False

ull T-Mobile
11:21 PM
22%
E LeetCode
* Pick One
Given an array nums of size n, return the majority
element.
The majority element is the element that appears
more than [n / 2] times. You may assume that
the majority element always exists in the array.
Example 1:
Input: nums =
[3,2,3]
Output: 3
Example 2:
Input: nums =
Output: 2
[2,2,1,1,1,2,2]
AA
leetcode.com

Process or set of rules that allow for the solving of specific, well-defined computational problems through a specific series of commands. This topic is fundamental in computer science, especially with regard to artificial intelligence, databases, graphics, networking, operating systems, and security.

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