### Effect of Garbanzo Beans on Aberrant Crypt Foci in RatsLegumes have various health benefits, including their high fiber content, which may lower the risk of colon cancer. An experiment was conducted to evaluate the effect of garbanzo beans on the presence of Aberrant Crypt Foci (ACF) in rats. The number of ACF is an indicator of the prevalence of colon cancer. In Treatment A, rats were fed 5% garbanzo beans, while Control rats (Treatment B) didn’t receive garbanzo beans in their diet. The data below represent the number of ACF in rats after 8 weeks of feeding.#### Data| Rat | Treatment A | Treatment B ||-----|-------------|-------------|| 1 | 30 | 35 || 2 | 23 | 35 || 3 | 27 | 40 || 4 | 30 | 31 || 5 | 35 | 30 || 6 | 35 | 40 || 7 | 30 | 25 |#### Hypothesis TestingThe researcher wants to evaluate the following hypothesis:- **H₀**: μA = μB (null hypothesis)- **Hₐ**: μA ≠ μB (alternative hypothesis)1. **P-value Calculation**: Determine the exact P-value for this experiment (use Excel, round to the nearest hundredth).2. **Decision Making**: Using α = 0.10, will you reject or fail to reject the null hypothesis? (Choose one, be careful with your spelling)---This text provides an overview of a scientific experiment with clear data presentation and outlines the decision-making process required in hypothesis testing.

The formula of the test statistic of the two sample t-test is,where, denotes the mean of first…

Answered: Legumes have various health benefits,…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Researchers have shown that cigarette smoking has a deleterious effect on lung function. In their study of the effect of cigarette smoking on the carbon monoxide diffusing capacity (DL) of the lung, Ronald Knudson, W. Kaltenborn and B. Burrows found that current smokers had DL readings significantly lower than either ex-smokers or nonsmokers. The carbon monoxide diffusing capacity for a random sample of current smokers was as follows: 103.768 88.602 73.003 123.086 91.052 92.295 61.675 90.677 84.023 76.014 100.615 88.017 71.210 82.115 89.222 102.754 108.579 73.154 106.755 90.479 Do these data indicate that the mean DL reading for current smokers is lower than 100, the average DL reading for nonsmokers? A. Find the test statistics and interpret the results, a = 0.01? B. Calculate p value and interpret the results. C. Find the confidence interval for a = 0.05.
Captivity can influence immunological responses in some mammals. Seeber et al. (2020) investigated various aspects of immunological responses in captive and free-ranging zebras. One aspect of the study involved samples of 12 free-ranging zebras from Namibia, 9 from Tanzania, and 38 captive zebras from various zoos in Europe. (All of these were non-lactating females.) One of the measured variables from blood samples was lysozyme concentration (μg/L). (Lysozyme is a biomarker of the immune response.) The researchers were interested in investigating possible differences in lysozyme concentration between zebras in the various locations. As part of the analysis, they carried out a one-way ANOVA on the lysozyme concentrations for the zebras from the 3 locations, and found the following output. Df Sum Sq Mean Sq F value Pr(>F) Location 2 50.65 25.33 42.24 6.54e-12Residuals 56 33.57 0.60 Suppose the assumptions of one-way ANOVA…
Researchers were curious to see if stress affected beta-endorphins. They took beta-endorphin levels for 19 patients 12 hours before surgery (lower stress) and again 10 minutes before surgery (higher stress). Given: SDd-bar = 13.52, SDx1 = 4.40
A deficiency of the trace element selenium in the diet can negatively impact growth, immunity, muscle and neuromuscular function, and fertility. The introduction of selenium supplements to dairy cows is justified when pastures have low selenium levels. Authors of a research paper supplied the following data on milk selenium concentration (mg/L) for a sample of cows given a selenium supplement (the treatment group) and a control sample given no supplement, both initially and after a 9-day period. Initial Measurement Treatment Control 11.4 9.1 9.6 8.7 10.1 9.7 8.5 10.8 10.2 10.9 10.6 10.6 11.9 10.1 9.9 12.3 10.7 8.8 10.2 10.4 10.3 10.9 11.4 10.4 9.3 11.6 10.6 10.9 10.9 8.3 After 9 Days Treatment Control 138.3 9.2 104 8.9 96.4 8.9 89 10.1 88 9.6 103.8 8.6 147.3 10.4 97.1 12.4 172.6 9.2 146.3 9.5 99 8.4 122.3 8.8 103 12.5 117.8 9.1 121.5 93 (a) Use the given data for the treatment group to determine if…
An article indicated that the biggest issue facing e-retailers is the ability to turn browsers into buyers. The article stated that less than 10% of browsers buy something from a particular website. A SRS of 2000 browsers was taken of which 180 made a purchase. Let alpha = .10.
Researchers suspect that drinking tea might enhance the production of interferon gamma, a molecule that helps the immune system fight bacteria, viruses, and tumors. A recent study involved 20 healthy people who did not normally drink tea or coffee. Ten of the participants were randomly assigned to drink five cups of tea a day, while 10 were asked to drink the same amount of coffee. After two weeks, blood samples were exposed to an antigen and production of interferon gamma were measured. The results are shown in the following table: Теа: 55 17 54 49 10 46 21 14 53 Coffee: 16 12 20 52 37 15 22 30 3 Let X ~ N(ux,o3) be the interferon gamma production for participants who drink tea and observations for the ten participants who drink tea are a random sample from X. Let Y ~ N(uy,o) be the interferon gamma production for participants who drink coffee and observations for the ten participants who drink coffee are a random sample from Y. Some R output that may help. > p1 qnorm(p1) [1] -2.326…
In a certain study, the effect on oat yield was compared for the Pallinup, Overberg and Magnifico varieties of oats and four different concentrations of manure (0, 0.2, 0.4 and 0.6 tonnes per acre). Identify the experimental units, response variable, factor(s), levels of each factor and treatments.
It has been hypothesized that allergies result from a lack of early childhood exposure to antigens. If this hypothesis were true, then we would expect allergies to be more common in very hygienic households with low levels of bacteria and other infectious agents. To test this theory, researchers at the University of Colorado sampled the houses of 61 children 9-24 months old and recorded two variables: (1) whether the child tested positive for allergies and (2) the concentration of bacterial endotoxin in the house dust (endotoxin units per ml, EU/ml)1. The following are the endotoxin levels at the homes of the 51 children tested negative for allergies. 708.23 911.60 976.81 1316.63 262.74 9772.08 370.76 229.16 2570.51891.19 3163.20 1777.65 1288.57 436.23 2631.63 1173.52 911.67 7942.42 740.32 356.92 1175.48 1480.55 2754.61 575.62 573.89 468.26 1000.71 364.22 1025.26 1022.04 645.41 363.57 977.47 1022.75 1860.63 371.13 174.73 399.68 1479.77 2882.96…
The effects of developer strength (factor A) and development time (factor B) on the density of photographic plate film were being studied. Two strengths and two development times were used, and four replicates in each of the four cells were evaluated. The results (with larger being best) are shown in the following table: At the 0.05 level of significance, a. is there an interaction between developer strength and development time? b. is there an effect due to developer strength? c. is there an effect due to development time?
An experiment to evaluate the effectiveness of the type of snack and children's perception of satiation was designed so that subjects aged 10 to 13 years were randomly assigned a snack that was of the exact same ingredients but described differently. The first group had their snack described as healthy and full of vitamins, the second group had their snack described as tasty, the third group were given a snack without any description whatsoever. Thirty minutes after finishing the snack, subjects were asked to rate their hunger on a scale of 1 to 10. The results are summarized in the table: ANOVA: Single Factor SUMMARY Groups Healthy Tasty No Description ANOVA Source of Variation Between Groups Within Groups Total Count 12 13. 14 SS 17.46154 62.89744 80.35897 Sum 62 46 56 Average 5.1667 3.5385 4.0000 Variance 1.9697 1.9359 1.3846 df MS F P-value 2 8.730769 4.997146 0.012156 36 1.747151 38 Based on these results, at a 5% level of significance what conclusion can the researchers draw from…
Do less agreeable Facebook users tend to spend more time on Facebook? A study (Ivcevic and Ambady, 2013) aimed to investigate various facets of use of the social networking website Facebook. Previous research suggested that individuals with poorer face-to-face social skills may find internet-based social platforms less daunting, so as part of the study Ivcevic and Ambady investigated whether an individual's volume of Facebook use was associated with levels of "agreeableness". The subjects were 99 university students who all had a Facebook page. The subjects agreed to allowing the content of their Facebook pages to be downloaded on six separate occasions over a three-week period. As part of the data gathered on each subject, each of the 99 were individually rated by a selected friend on an "agreeableness" scale (based on average ratings on a questionnaire where all responses were on a Likert scale), with 1 being "low" and 5 "high". We consider here the relationship between "friend…

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