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Left se ky kapek by -4.0cm Right @which capacitor plate is the positive plake? what is the electric field direction and magnitude? what are the electric potential at point a, b, and I? What is the electric potential energy an election at the midpoint (c) 0

Left se ky kapek by -4.0cm Right @which capacitor plate is the positive plake? what is the electric field direction and magnitude? what are the electric potential at point a, b, and I? What is the electric potential energy an election at the midpoint (c) 0

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### Diagram and Questions on Capacitor **Diagram Description:** The diagram shows a parallel plate capacitor with two vertical plates, labeled "Left" and "Right." The left plate is labeled with a potential of 400V, and the right plate is labeled with 0V. The distance between the plates is 4.0 cm. Three points, labeled \(a\), \(b\), and \(c\), are positioned between the plates, with \(c\) being the midpoint. **Questions:** **(a)** Which capacitor plate is the positive plate? **(b)** What is the electric field direction and magnitude? **(c)** What are the electric potentials at points \(a\), \(b\), and \(c\)? **(d)** What is the electric potential energy of an electron at the midpoint (\(c\)) of the capacitor?
Transcribed Image Text:### Diagram and Questions on Capacitor **Diagram Description:** The diagram shows a parallel plate capacitor with two vertical plates, labeled "Left" and "Right." The left plate is labeled with a potential of 400V, and the right plate is labeled with 0V. The distance between the plates is 4.0 cm. Three points, labeled \(a\), \(b\), and \(c\), are positioned between the plates, with \(c\) being the midpoint. **Questions:** **(a)** Which capacitor plate is the positive plate? **(b)** What is the electric field direction and magnitude? **(c)** What are the electric potentials at points \(a\), \(b\), and \(c\)? **(d)** What is the electric potential energy of an electron at the midpoint (\(c\)) of the capacitor?
Expert Solution
Step 1

(a) The left plate is positive and it is at higher potential, so left plate is the positive plate. 

(b) Electric field lines start are away from the positive charges and move towards negative charge 

So, the electric field lines move from left to right.

The electric field strength is given as 

E=∆Vd

where E is the electric field strength, ∆V is the potential difference and d is the distance between plates 

The potential difference is 

∆V=400 V-0 V∆V=400 V

Substitute the values 

E=400 V4 cmE=400 V0.04 mE=10000 V/m

 

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