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lease check if my answers are correct. The given is the first two columns while my answers are in the third and fourth

lease check if my answers are correct. The given is the first two columns while my answers are in the third and fourth

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Please check if my answers are correct. The given is the first two columns while my answers are in the third and fourth column

Percentage Deviation (using Eq. 8) Time of fall Deviation Trial t(s) d; = t; - tave ld P.D., = 4 x 100 P.D.1 P D., = 0.709% -0.003| 0.423 x 100 1 di = 0.420 – 0.423 =- 0.003 0.420 d2 = t2 - tave d, = 0.409 – 0.423 d, =- 0.014 P D. = x 100 PD = P.D., = 3.31% P.D.3= 2 I-0.014 0.423 х 100 0.409 x 100 dz = t3 - tave dz = 0.419 – 0.423 dz =- 0.004 3 I-0.004 0.423 х 100 P.D.3 |P.D = 0.946% 0.419 P.D. = 10.007 P.D.4 х 100 4 d, = 0.430 – 0.423 d4 = 0.007 sAD - 1 = *p х 100 %3D 0.423 0.430 P.D.4 = 1.65% P.D.3 = х 100 ds = ts - tave ds = 0.419 – 0.423 d4 =- 0.004 5 P.D, = -0.004 0.423 x 100 0.419 P.D. = 0.946%
Transcribed Image Text:Percentage Deviation (using Eq. 8) Time of fall Deviation Trial t(s) d; = t; - tave ld P.D., = 4 x 100 P.D.1 P D., = 0.709% -0.003| 0.423 x 100 1 di = 0.420 – 0.423 =- 0.003 0.420 d2 = t2 - tave d, = 0.409 – 0.423 d, =- 0.014 P D. = x 100 PD = P.D., = 3.31% P.D.3= 2 I-0.014 0.423 х 100 0.409 x 100 dz = t3 - tave dz = 0.419 – 0.423 dz =- 0.004 3 I-0.004 0.423 х 100 P.D.3 |P.D = 0.946% 0.419 P.D. = 10.007 P.D.4 х 100 4 d, = 0.430 – 0.423 d4 = 0.007 sAD - 1 = *p х 100 %3D 0.423 0.430 P.D.4 = 1.65% P.D.3 = х 100 ds = ts - tave ds = 0.419 – 0.423 d4 =- 0.004 5 P.D, = -0.004 0.423 x 100 0.419 P.D. = 0.946%
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