Learning Task 2 - Applying the rules of refraction for converging and diverging lens, drawa ray diagram for the following given situations and describe the characteristics of theimages formed in terms of location (L), orientation (O), size(S), and type (T).A. Converging Lens1. The object is located at 2F2. The object is located between 2F and FObjectObjectI. f.2FI.O2F F2F3. The object is located at F4. The object is in front of FObjectObjectFF2F6. The object is 2F and F2F FB. Diverging Lens5. The object is beyond 2F2F F2F|42FF2F

The location or distance of an image produced by a lens can be found using the lens equation as…

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The side-view mirrors of most cars are convex spherical mirrors (so that the driver can see a wider angle behind the car). Suppose that the side view mirror of your car has a radius of curvature of 18 m, and that another car is 10 m in front of the mirror (behind the car). Ignore any aberration. a) Using the mirror equation to calculate how far the other car appears to be from the mirror. b) Sketch a light ray diagram including the object, the mirror, the image, and the principal light rays. c) Is the image distance smaller or larger than the object distance? Is the image smaller or larger than the object? Answer with calculations.
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Question 3 Below is a scale drawing of a lens with a focal length f = 15 cm with an object located a distance d, = 20 cm to the left of the lens. The circles mark the locations of the focal points, 15 cm to either side of the lens. In the next activity you will set up an object 20 cm from a 15 cm focal length lens, and locate the position at which the image is formed. Make a ray diagram for this situation, following the steps given in Activity 1.2. Use the ray diagram to determine the distance from the lens to the image that will be formed. Object 1
1.)The diverging lens of the figure produces an image of an object to the left of the lens and 5.00 cm away from the center of the lens. The refracting index of the lens is 1.50. The magnitude of the focal length of the lens is 12.0 cm and the radius of curvature R1 is 15.0 cm. A.) Calculate the radius of curvature R2 of the lens. Show your work. B.) Fill in the following table with the focal length of the lens, the distance of the image and the distance of the object (you have to calculate that) with the correct signs! f s s' C.) Is the object to the left or to the right of the lens? (Select one.) D.) Is the image formed by the lens upright or inverted compared to the object? (Select one.)
When considering the location of images formed by lenses, we often like to employ ray tracing diagrams. To do this we draw three rays of light and see where they intersect. 1. A ray parallel to the axis refracts through the far focal point. 2. A ray that enters the lens along a line through the near focal point emerges parallel to the axis. 3. A ray through the center of the lens does not bend. This method was shown to you in class for the following situation: An object and converging lenses with the distance to the object being greater than the focal length, do > f. object focal point do focal point Now you will complete the ray tracing diagram for an object that is closer than the focal length: de focal point image Answer the following based on your ray tracing: (a) Is the image real or virtual? (b) is the image larger or smaller than the object? focal point
Problem 6 Images May Move Faster or Slower An object moves towards a concave mirror at speed up. (a) Show that the speed of the image is: Vo υ (1-2)² where R is the radius of curvature of the mirror. (b) Plot the velocity of the image as a function of the position of the object. Label where the image is real and where it is virtual.
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Part 3 - Keplerian Telescope A telescope magnifies far-off images. Rays hitting the objective are almost parallel and are focused to form an inverted, real image at the focal point of the eyepiece. The eyepiece refracts the light so the rays leave the eyepiece again almost parallel. The object remains inverted, and so the angular magnification is defined as M= -B/a, where the angles are shown in Figure 2. objective eyepiece f. f. f. F e F. h inverted image at infinity Figure 2: A Keplerian telescope, invented by Johannes Kepler in 1611, uses two converging lenses as shown. An objective with focal length fo and an eyepiece with focal length fe focus nearly parallel light rays from a distant object into an inverted image of much smaller size than the object. 1. Assume that a and ß are small angles (much less than 1 radian). Using the ray diagram shown in Figure 2 and considering two appropriate triangles, show that M = -fo/ fe.