The diverging lens of the figure produces an image of an object to the left of the lens and 5.00 cm away from the center of the lens. The refracting index of the lens is 1.50. The magnitude of the focal length of the lens is 12.0 cm and the radius of curvature R1 is 15.0 cm. A.) Calculate the radius of curvature R2 of the lens. Show your work. B.) Fill in the following table with the focal length of the lens, the distance of the image and the distance of the object (you have to calculate that) with the correct signs!

The diverging lens of the figure produces an image of an object to the left of the lens and 5.00 cm away from the center of the lens. The refracting index of the lens is 1.50. The magnitude of the focal length of the lens is 12.0 cm and the radius of curvature R1 is 15.0 cm. A.) Calculate the radius of curvature R2 of the lens. Show your work. B.) Fill in the following table with the focal length of the lens, the distance of the image and the distance of the object (you have to calculate that) with the correct signs!

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How do I go about the diagram drawing? The lamp is placed 6.7 cm from convex lens 1 that has a focal distance of 2.5 cm. This lens is placed2.5 cm from another lens that also has a focal distance of 2.5 cm. Locate the final image of the object and theover-all magnification by completing the chart below. Show all work.Draw a ray diagram to verify the image’s placement.
For the following lens, locate the image by drawing a ray diagram (3 rays) and describe the image as (inverted or upright, real or virtual, magnified or reduced). Converging lens a. Upright, virtual, reduced b. Inverted, real, magnified c. Inverted, virtual, magnified d. Upright, real, reduced
- Part A Consider a typical convex passenger-side mirror with a focal length of -80 cm. A 1.7-m-tall cyclist on a bicycle is 25 m from the mirror. You are 1.4 m from the mirror, and suppose, for simplicity, that the mirror, you, and the cyclist all lie along a line. How far are you from the image of the cyclist? Express your answer with the appropriate units. μΑ L = Value Units Submit Request Answer Part B What is the image height? Express your answer with the appropriate units. HA h' = Value Units %3D
When considering the location of images formed by lenses, we often like to employ ray tracing diagrams. To do this we draw three rays of light and see where they intersect. 1. A ray parallel to the axis refracts through the far focal point. 2. A ray that enters the lens along a line through the near focal point emerges parallel to the axis. 3. A ray through the center of the lens does not bend. This method was shown to you in class for the following situation: An object and converging lenses with the distance to the object being greater than the focal length, do > f. object focal point do focal point Now you will complete the ray tracing diagram for an object that is closer than the focal length: de focal point image Answer the following based on your ray tracing: (a) Is the image real or virtual? (b) is the image larger or smaller than the object? focal point
help with image properties pls also all the units suppose to cm?
Direction: Identify if the statement is a concave or convex mirroriens 1 Also called as a diverging lens 2. Reflective surface bulges towards the light source. 3. Also called as a converging mirror 4. The parallel light rays intersect at a focal point after reflection 5 Reflective surface bulges away from the light source 6. Positive focal length of a mirror 7. Lens with a thicker center 8. A lens that forms upright and reduced images. 9 A thinner center lens. 10. Lens that forms real and virtual images. 11. Converging lens is also known as. 12. Lens with a thinner edges. 13. Lens with a thicker edges. 14. Image located behind the mirror 15. Mirror with an inverted image. 16. q + of the lens 17. Negative focal length of the mirror 18. h'- of the mirror 19. h'+ of the lens 20. q- of the mirror 21. A mirror which is very dependent of the object positions. 22. Lens that can always produce a virtual image. 23. Mirror that is always upright. 24. Lens with the image formation on the object…
Convex and Concave Lens (а.) (b.) In the above figures f is located at the focal point of the lens. For each statement select True or False. False O An object placed to the left of f and the lens in Fig. b produces a real image. False An object placed to the left of f in Fig. a results in an image on the right side of the lens. O An object placed to the left of f and the lens in Fig. a produces a virtual image. O An object placed betweenf and the lens in Fig. a produces a virtual image. O An object placed to the left of f in Fig. b results in an image on the right side of the lens. O An object placed between f and the lens in Fig. a results in an image on the left side of the lens. O The lens in Fig. a is a converging lens. False True False False True Submit Answer Incorrect. Tries 4/6 Previous Tries
Radius of curvature of a converging lens is 80 cm. If an object of height 10 cm is placed at a distance of 20 cm from lens on the principal axis, find : a. image distance b. image height c. Draw ray diagram
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An object stands on the common central axis of two thin, symmetric lenses. The object is placed 15.0 cm in front of the first lens (converging lens) whose focal length is 10.0 cm. The second lens is a diverging lens whose focal length is also 12.0 cm. The distance between the lenses is 40.0 cm. a.) Determine the characteristics of the final image by using thin-lens and magnification equations. Give your reasoning. b.) Find the location of the final image by using ray diagrams (sketch the rays clearly). Object f₁ 15 cm 1st Lens f₁ 40 cm 420 2nd Lens
please answer 4 and 5, thank you
2. Spherical (Curved) Mirrors - Concave Mirror An object is placed at a distance of 15cm in front of a concave mirror whose focal length if 10.5 cm. A. What is the image distance? Please draw a Ray Diagram AND Use the Mirror Equation to Find the Image. B. What is the magnification? ). 1 1 + do di 1 ƒ f = R Skill: Use 3 Principal Rays to Draw a Ray Diagram and Find the Image m= h₁ ho Skill: Use the Mirror Equation to Algebraically Solved for Image Distance, then Solve for Magnification d₁ do