Learning Task 1: Find the value of the expression given the value of the variables 1. 3x +5; x 2 4. 3(xy + 6); x -6 and y-1 2. 5xy + x - 4, x -3 and y = 5 5. 2x+5 x = -3 and y = -8 %3D 3. 6ab-c; a=5; b 3; c 10 3x-y abc
Learning Task 1: Find the value of the expression given the value of the variables 1. 3x +5; x 2 4. 3(xy + 6); x -6 and y-1 2. 5xy + x - 4, x -3 and y = 5 5. 2x+5 x = -3 and y = -8 %3D 3. 6ab-c; a=5; b 3; c 10 3x-y abc
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
Related questions
Question
Answer Learning Task 1, 2, and 3

Transcribed Image Text:Algebraic expressions are said to be similar if the expressions has the
same literal coefficients or variables, like 3x and x are similar while x and x2 are
St
not.
Yc
In general, algebraic expressions are called polynomials. You can only per-
AL
form addition and subtraction to polynomials that are similar.
as a letter that represents a
In the previous lesson you define variables
number. An expression can have a value if you replace the variable with a number
and perform the operations involved.
The terms in the expression 3x + 5 are not similar, hence you cannot add
them. However if you give value to x, then you can perform the operations.
2.
Example:
1. Find the value of 3x + 5, if x = 2
Solution: 3x + 5 = 3(2) + 5 = 6 + 6 = 11.
LMD
The value of the expression 3x + 5 is 11 when x = 2.
2. Find the value of 6ab-C if a= 5; b = 3; c = 10
abc
6(5)(3) – 10
5(3)(10)
Solution:
6ab -c
80
abc
150
15
Rules in Adding or Subtract Polynomials
Step 1. Arrange the polynomial in descending or ascending order if possible.
Step 2. Group Terms which are similar.
Step 3. Add/subtract the numerical coefficients, applying the rules in subtracțing
and adding integers and copy the literal coefficients.
Examples:
1. Add: 4x2 - 2x +5 and 7+5x3 + 4x - x2
D
Learning Task 1: Find the value of the expression given the value of the variables
1. Зх + 5; х%3D2
4. 3(xy + 6); x= -6 and y-1
2. 5xy + x- 4,
x = -3 and y = 5
5. 2x +5 x = -3 and y = -8
3.
6ab-c; a=5; b 3; c = 10
3x-y
abc
SUKAS

Transcribed Image Text:Learning Task 2:
A. Evaluate the algebraic expressions
ap
Let a = 4, b = -5, c 0.6, x = -3, y 0.4; z =
Algebraic Expression
ba
Value
ex
Value
Algebraic Expression
II
1. 3abc + bc - a
6. 3x2 + 2xy - 3(ab)2
th
2. bxy + 5ab - ay
7. 25 2x2y +3a2b- az2
3. abz - 8z +b
8. (az)2 + 5x²y - 4bc
9. 2x2y2-12abz
16
4. ax + by - cz
5. 4ax + cz
10. 8z3-4x + y2
B. Perform the indicated operations
Subtract:
Add
1. (5x - 3x2 + 4) + (6x3 - 4x2 - 7)
6. (5x3 - 7x2 + 3x – 4) –(8x3 + 2x2 +3x - 7)
2.-7x°y + 4x²y2 - 2 and 4x³y + 1-8x2y2
7. (2x2y - 5xy + 3y2) – (7xy – 6y² + 5x²y)
3. (5+ 24y3- 7y²) + (-6y3 + 7y2 + 5)
8. (9x5 - 6x³ + 7x²) – (7x³ – 6x5 + 2x²)
4. (2x5-6x3 - 12x2 - 4) + (-11x5 + 8x + 2x2 + 6)
9. Subtract 4x3 - 5x - 8 from 6x2 – 3x + 8
5. (3y3- 2y + y4 + 2y3 + 5) and (2y5 + 3y3 + 2+ 7) | 10. (1.5y³ + 4.8y2 + 12) - (y- 1.7y2 + 2y)
Learning Task 3: Solve the following. Do this in a separate sheet of paper.
1. A box is ( 2x-3) by ( x + 5) by ( 3x +1) , what is the volume of the box if x = 3
cm?
bh
If the base (b) = 10 cm and
2. The formula for the area of a triangle is A=
the height (h) = 6 cm, what is the area of the triangle?
3. The length (1) of the rectangle is x2 + 2x - 3 and the width (w) is 5x + 4, what
is the perimeter of the rectangle.
4. From the sum of 3x3 + 7x2 - 5 and 2x2 + 3x + 8 take away 5x2 + x -5.
to mue srí
5. What should be added to 3x3 + 4x2 -7 to have a sum of 4x3 + x2 + 5.
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