Learning Goal: To understand the effect of the load resistance on the output voltage for a voltage divider. The circuit shown below can be viewed as a voltage divider. This circuit can be used to generate a new lower voltage 1, from an input DC voltage 1, Part A Find the value of R₂ required if t, 12 V. R₁ = 30 kf2. and the desired no-load output voltage is t = 4 V Express your answer in kf2 to three significant figures. You did not open hints for this part. ANSWER: When there is no load attached, the output voltage is UoUg. The load is attached in parallel with R₂. The equivalent resistance of the load and R₂ in parallel will always be smaller than the resistance of R₂ alone, so the output voltage must decrease. For a given load resistance R. the output voltage is R₁+R₂ VoRi (1+R₂/R)+R₂8- R₂ R₂ = Up kQ Part B Several different loads are going to be used with the voltage divider from Part A. If the load resistances are 300 kf2, 200 kf2, and 100 k2, what is the output voltage that is the most different from the design output voltage 1, = 4 V? Express your answer in V to three significant figures. You did not open hints for this part. ANSWER: R₁ = R₁ to + R₂3 V R₁ Part C The circuit designer wants to change the values of R₁ and R₂ so that the design output voltage 1,4 V is achieved when the load resistance is R200 kf2 rather than at no-load. The actual output voltage must not drop below 3.6 V when R100 k2. What is the smallest resistor value that can be used for R₂? Express your answer in k2 to three significant figures. You did not open hints for this part ANSWER: ΚΩ
Learning Goal: To understand the effect of the load resistance on the output voltage for a voltage divider. The circuit shown below can be viewed as a voltage divider. This circuit can be used to generate a new lower voltage 1, from an input DC voltage 1, Part A Find the value of R₂ required if t, 12 V. R₁ = 30 kf2. and the desired no-load output voltage is t = 4 V Express your answer in kf2 to three significant figures. You did not open hints for this part. ANSWER: When there is no load attached, the output voltage is UoUg. The load is attached in parallel with R₂. The equivalent resistance of the load and R₂ in parallel will always be smaller than the resistance of R₂ alone, so the output voltage must decrease. For a given load resistance R. the output voltage is R₁+R₂ VoRi (1+R₂/R)+R₂8- R₂ R₂ = Up kQ Part B Several different loads are going to be used with the voltage divider from Part A. If the load resistances are 300 kf2, 200 kf2, and 100 k2, what is the output voltage that is the most different from the design output voltage 1, = 4 V? Express your answer in V to three significant figures. You did not open hints for this part. ANSWER: R₁ = R₁ to + R₂3 V R₁ Part C The circuit designer wants to change the values of R₁ and R₂ so that the design output voltage 1,4 V is achieved when the load resistance is R200 kf2 rather than at no-load. The actual output voltage must not drop below 3.6 V when R100 k2. What is the smallest resistor value that can be used for R₂? Express your answer in k2 to three significant figures. You did not open hints for this part ANSWER: ΚΩ
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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