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Learning Goal: To apply Problem-Solving Strategy 2.2 Relative velocity. The wind is blowing from west to east at 27.0 miles/hour, and an eagle in that wind is flying at 15.0 miles/hour relative to the air. What is the velocity of this eagle relative to a person standing on the ground if the eagle is flying from west to east relative to the air? Take the positive x axis to point toward the east. Problem-Solving Strategy 2.2 Relative velocity Note the order of the double subscripts on the velocities; VA/B always means "the velocity of A (first subscript) relative to B (second subscript)." These subscripts obey an interesting kind of algebra. If we regard each one as a fraction, then the fraction on the left side is the product of the fractions on the right side: For a point P relative to frame A, P/A = (P/B)(B/A). This is a handy rule to use when you solve problems involving relative velocities. If there are three different frames of reference, A, B, and C, we can write immediately VP/A = VP/C+VC/B + VB/A+ and so on. The sum in this equation is always an algebraic sum, and any or all of the velocities may be negative. SET UP Before writing any equations, organize your information and draw appropriate diagrams. Part A What is the velocity of the air relative to a person standing on the ground, VA/P? What is the velocity of the eagle relative to the air, VE/A? Enter your answers in miles per hour to three significant figures. Separate VA/P from UE/A with a comma. Ο ΑΣΦ ? VA/P,VE/A = 42.0 miles/hour, miles/hour Your submission doesn't have the correct number of answers. Answers should be separated with a comma. No credit lost. Try again.

Learning Goal: To apply Problem-Solving Strategy 2.2 Relative velocity. The wind is blowing from west to east at 27.0 miles/hour, and an eagle in that wind is flying at 15.0 miles/hour relative to the air. What is the velocity of this eagle relative to a person standing on the ground if the eagle is flying from west to east relative to the air? Take the positive x axis to point toward the east. Problem-Solving Strategy 2.2 Relative velocity Note the order of the double subscripts on the velocities; VA/B always means "the velocity of A (first subscript) relative to B (second subscript)." These subscripts obey an interesting kind of algebra. If we regard each one as a fraction, then the fraction on the left side is the product of the fractions on the right side: For a point P relative to frame A, P/A = (P/B)(B/A). This is a handy rule to use when you solve problems involving relative velocities. If there are three different frames of reference, A, B, and C, we can write immediately VP/A = VP/C+VC/B + VB/A+ and so on. The sum in this equation is always an algebraic sum, and any or all of the velocities may be negative. SET UP Before writing any equations, organize your information and draw appropriate diagrams. Part A What is the velocity of the air relative to a person standing on the ground, VA/P? What is the velocity of the eagle relative to the air, VE/A? Enter your answers in miles per hour to three significant figures. Separate VA/P from UE/A with a comma. Ο ΑΣΦ ? VA/P,VE/A = 42.0 miles/hour, miles/hour Your submission doesn't have the correct number of answers. Answers should be separated with a comma. No credit lost. Try again.

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Learning Goal: To apply Problem-Solving Strategy 2.2 Relative velocity. The wind is blowing from west to east at 27.0 miles/hour, and an eagle in that wind is flying at 15.0 miles/hour relative to the air. What is the velocity of this eagle relative to a person standing on the ground if the eagle is flying from west to east relative to the air? Take the positive x axis to point toward the east. Problem-Solving Strategy 2.2 Relative velocity Note the order of the double subscripts on the velocities; VA/B always means "the velocity of A (first subscript) relative to B (second subscript)." These subscripts obey an interesting kind of algebra. If we regard each one as a fraction, then the fraction on the left side is the product of the fractions on the right side: For a point P relative to frame A, P/A = (P/B)(B/A). This is a handy rule to use when you solve problems involving relative velocities. If there are three different frames of reference, A, B, and C, we can write immediately VP/A = VP/C+VC/B + VB/A+ and so on. The sum in this equation is always an algebraic sum, and any or all of the velocities may be negative. SET UP Before writing any equations, organize your information and draw appropriate diagrams. Part A What is the velocity of the air relative to a person standing on the ground, VA/P? What is the velocity of the eagle relative to the air, VE/A? Enter your answers in miles per hour to three significant figures. Separate VA/P from UE/A with a comma. Ο ΑΣΦ ? VA/P,VE/A = 42.0 miles/hour, miles/hour Your submission doesn't have the correct number of answers. Answers should be separated with a comma. No credit lost. Try again.
Transcribed Image Text:Learning Goal: To apply Problem-Solving Strategy 2.2 Relative velocity. The wind is blowing from west to east at 27.0 miles/hour, and an eagle in that wind is flying at 15.0 miles/hour relative to the air. What is the velocity of this eagle relative to a person standing on the ground if the eagle is flying from west to east relative to the air? Take the positive x axis to point toward the east. Problem-Solving Strategy 2.2 Relative velocity Note the order of the double subscripts on the velocities; VA/B always means "the velocity of A (first subscript) relative to B (second subscript)." These subscripts obey an interesting kind of algebra. If we regard each one as a fraction, then the fraction on the left side is the product of the fractions on the right side: For a point P relative to frame A, P/A = (P/B)(B/A). This is a handy rule to use when you solve problems involving relative velocities. If there are three different frames of reference, A, B, and C, we can write immediately VP/A = VP/C+VC/B + VB/A+ and so on. The sum in this equation is always an algebraic sum, and any or all of the velocities may be negative. SET UP Before writing any equations, organize your information and draw appropriate diagrams. Part A What is the velocity of the air relative to a person standing on the ground, VA/P? What is the velocity of the eagle relative to the air, VE/A? Enter your answers in miles per hour to three significant figures. Separate VA/P from UE/A with a comma. Ο ΑΣΦ ? VA/P,VE/A = 42.0 miles/hour, miles/hour Your submission doesn't have the correct number of answers. Answers should be separated with a comma. No credit lost. Try again.
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