(b) Is the motion of the rock one with constant velocity or constant acceleration? Choose an appropriate equation of motion to calculate the height of the cliff. Something to think about: Do you need to split the trip into two parts: 1. the rock's journey up, and 2. the rock's journey down? Is it possible to solve without splitting the motion into two parts? Ay=vt Ay = (vo+ v)₁ t 2 v=v₁ + at ✓= √²+2aAy 1 Ay= Vot+2 -at² (c) Calculate the height of the cliff. Note: The height of the cliff should be a positive value. Enter to 3 significant figures h= t= m (d) How long would it take the rock to reach the ground if it is thrown straight down with the same speed instead of up? Enter to 3 significant figures S Sense-making: Check if the answer in part (d) is less than the time in part (a).
Displacement, Velocity and Acceleration
In classical mechanics, kinematics deals with the motion of a particle. It deals only with the position, velocity, acceleration, and displacement of a particle. It has no concern about the source of motion.
Linear Displacement
The term "displacement" refers to when something shifts away from its original "location," and "linear" refers to a straight line. As a result, “Linear Displacement” can be described as the movement of an object in a straight line along a single axis, for example, from side to side or up and down. Non-contact sensors such as LVDTs and other linear location sensors can calculate linear displacement. Non-contact sensors such as LVDTs and other linear location sensors can calculate linear displacement. Linear displacement is usually measured in millimeters or inches and may be positive or negative.
![(b) Is the motion of the rock one with constant velocity or constant acceleration?
+
Choose an appropriate equation of motion to calculate the height of the cliff.
Something to think about: Do you need to split the trip into two parts: 1. the rock's journey up, and
2. the rock's journey down? Is it possible to solve without splitting the motion into two parts?
Ay = vt
Ay = (v₁ + v)
2
V = V₁ + at
✓²=²+2aAy
Ay=vot+ = at²
(c) Calculate the height of the cliff. Note: The height of the cliff should be a positive value.
Enter to 3 significant figures
h=
✔m
(d) How long would it take the rock to reach the ground if it is thrown straight down with the same
speed instead of up?
Enter to 3 significant figures
t=
✔S
Sense-making: Check if the answer in part (d) is less than the time in part (a).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F003be4cf-16a8-4c58-b6a8-fd2c192ebcf0%2F0243c199-ceee-476a-9185-67bd5def1cf3%2Fggxk1wb_processed.png&w=3840&q=75)
![1. The solution to Part 1 should have looked like this.
Consider the sketch below. Adjust the colored sliders so that the corresponding
vo, V, and a vectors are oriented in the correct directions.
a =
Top of cliff
t=
Yo
Y
✔m/s
✔m/s²
✔ S
VO
↓.
a
Bottom of cliff
Y
Vo
It takes 2 s for a rock to hit the ground when it is thrown straight up from a cliff with an initial velocity
of 7.00 m/s. Assume all values are correct upto 3 significant figures.
V
(a)
• Using the notation Ay=y-yo for displacement, y for position after time t, yo for the initial
position, v for velocity after time t, vo for initial velocity, and a for acceleration, determine
what quantities are known and what are unknown.
• Enter the values of some known quantities below.
• Make sure you account for the signs of the vectors using the coordinate system used in
Part 1.
Enter to 3 significant figures
Vo =
a](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F003be4cf-16a8-4c58-b6a8-fd2c192ebcf0%2F0243c199-ceee-476a-9185-67bd5def1cf3%2F29lk99q_processed.png&w=3840&q=75)
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