**Physics Problem on Motion****(b) Motion Analysis**- Question: Is the motion of the rock characterized by constant velocity or constant acceleration?- Selection: Use the dropdown menu to choose the correct type of motion.**Equation Selection for Cliff Height Calculation**- Task: Choose an appropriate equation of motion to determine the height of the cliff.- **Consideration**: - Do you need to divide the rock's motion into two phases: 1. the ascent, and 2. the descent? - Can the problem be solved without dividing the motion?**Equations of Motion:**1. \( \Delta y = vt \)2. \( \Delta y = \frac{(v_0 + v)}{2} t \)3. \( v = v_0 + at \)4. \( v^2 = v_0^2 + 2a\Delta y \)5. \( \Delta y = v_0 t + \frac{1}{2} at^2 \)**(c) Height Calculation**- Task: Compute the height of the cliff. The result should be positive.- Input Format: Enter to 3 significant figures - \( h = \) [Input box] m**(d) Time Calculation for Descent**- Task: Calculate the time taken for the rock to hit the ground if it is thrown straight down with the same speed.- Input Format: Enter to 3 significant figures - \( t = \) [Input box] s**Sense-Making**- Verify if the time calculated in part (d) is less than the time in part (a). ### Transcription and Explanation for Educational Website:1. **Solution Overview**: The provided solution shows how Part 1 should have been structured using vectors to represent motion.2. **Diagram Description**: - The diagram illustrates the motion of a rock thrown vertically from a cliff. - Vectors are shown for initial velocity \( v_0 \), final velocity \( v \), and acceleration \( a \). - The top of the cliff is labeled \( y_0 \), and the bottom of the cliff is marked as the end point for \( y \).3. **Vector Orientation**: - \( v_0 \) (initial velocity) is directed upwards (blue arrow). - \( v \) (final velocity) is directed downwards (green arrow). - \( a \) (acceleration due to gravity) points downward (red arrow).4. **Problem Context**: - It takes 2 seconds for the rock to hit the ground after being thrown with an initial velocity of 7.00 m/s. - Calculations should consider up to 3 significant figures.5. **Instructions (Part a)**: - Use \(\Delta y = y - y_0\) for displacement. - Identify known and unknown quantities using the variables: - \( y \): Position after time \( t \) - \( y_0 \): Initial position - \( v \): Velocity after time \( t \) - \( v_0 \): Initial velocity - \( a \): Acceleration - Enter values for known quantities, ensuring vector signs match the diagram.6. **Input Fields for Known Quantities**: - \( v_0 = \) [Enter value] m/s - \( a = \) [Enter value] m/s\(^2\) - \( t = \) [Enter value] sThis setup guides students through a physics problem involving projectile motion, emphasizing vector orientation and accurate calculation.

Name: **Physics Problem on Motion****(b) Motion Analysis**- Question: Is th
Uploaded: 2024-03-05T11:56:34.000Z
Channel: Bartleby
Description: **Physics Problem on Motion****(b) Motion Analysis**- Question: Is the motion of the rock characterized by constant velocity or constant acceleration?- Selection: Use the dropdown menu to choose the correct type of motion.**Equation Selection for Cl