Large samples of women and men are obtained, and the hemoglobin level is measured in each subject. Here is the95% confidence interval for the difference between the two population means, where the measures from womencorrespond to population 1 and the measures from men correspond to population 2:- 1.76 g/dL < µ, - H2 < - 1.62 g/dL. Complete parts (a) through (c) below.a. What does the confidence interval suggest about equality of the mean hemoglobin level in women and themean hemoglobin level in men?Because the confidence intervalincludes95% , it appears that thereisa significant differencebetween the mean level of hemoglobin in women and the mean level of hemoglobin in men.(Type an integer or a decimal. Do not round.)b. Write a brief statement that interprets that confidence interval.O A. There is 95% confidence that the interval from - 1.76 g/ dL to - 1.62 g/ dL actually contains the valueof the difference between the two population means (H1 -42)O B. There is 95% confidence that the interval from - 1.76 g/ dL to - 1.62 g/ dL does not contain the valueof the difference between the two population means (u,-H).Vi(1,1)MoreO Time Remaining: 01:39:40Next>>8:39 a. m.P3Escritorio19°CESP11/12/202insertDeF6F7FRFOF10*Back7JOO

According to the given information in this question we need to answer a and b A) Because the…

Answered: Large samples of women and men are…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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7. What is the 95% confidence interval for the difference in the population means, µ1 - µ2, given the data from the two independent samples: n1 =56, x1= 58.2, s1= 4.3, n2=45, x2=60.2, s2=5.5 B. [-3.28 , -0.72] C. [-3.60, -0.40] D. [-3.65 , -0.35] A. [-3.96 , -0.04] 8. What is the 98% confidence interval for the difference in the population means, µ1 - µ2, given: n1= 22, x1= 41.4, s1= 5.9, n2= 19, x2= 43.2, s2= 6.5 D. [-3.48 , -0.12] B. [-3.07 , -0.53] A. [-3.12, -0.48] C. [-3.18, -0.42]
Using a significance level of α = 0.05, state your conclusion in terms of H0.?
Women are recommended to consume 1790 calories per day. You suspect that the average calorie intake is smaller for women at your college. The data for the 15 women who participated in the study is shown below: 1959, 1908, 1789, 1544, 1805, 1656, 1899, 1811, 1686, 1688, 1687, 1943, 1612, 1789, 1467 Assuming that the distribution is normal, what can be concluded at the α = 0.05 level of significance? For this study, we should use The null and alternative hypotheses would be: H0: H1: The test statistic = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is α Based on this, we should the null hypothesis. Thus, the final conclusion is that ... The data suggest the population mean is not significantly less than 1790 at α = 0.05, so there is sufficient evidence to conclude that the population mean calorie intake for women at your college is equal to 1790. The data suggest the populaton…
(3) If you are evaluating two different sets of measurements 0.952(7) atm and 0.977(5) atm. Are they statistically equivalent?
How large should a sample be to estimate the population mean within [68.71, 71.29] with a 99% confidence interval if the sample mean is 70 and the population variance was 9 Select one: a. n= 26 b. n= 46 C. n= 16 O d. n= 36
Data for fuel economy ratings in mi/gal for different cars are listed below. Each pair of data represents the rating using the Old test and the New test. Old (x) 31 22 23 33 27 21 22 19 31 16 New (y) 25 17 26 26 23 18 19 16 28 19 Find the best predicted value for the New test method given that the Old test method rating was 26. Use a significance level of 0.05.Round your answer to 1 decimal place, if needed.
Is the proportion of wildfires caused by humans in the south lower than the proportion of wildfires caused by humans in the west? 360 of the 501 randomly selected wildfires looked at in the south were caused by humans while 435 of the 588 randomly selected wildfires looked at the west were caused by humans. What can be concluded at the = 0.10 level of significance? For this study, we should use Select an answer t-test for the difference between two dependent population means z-test for the difference between two population proportions t-test for a population mean t-test for the difference between two independent population means z-test for a population proportion The null and alternative hypotheses would be: Select an answer μ1 p1 Select an answer < ≠ > = Select an answer μ2 p2 (please enter a decimal) Select an answer μ1 p1 Select an answer > ≠ < = Select an answer p2 μ2 (Please enter a decimal) The test statistic ? z t = (please show your…
Construct a 99% confidence interval for u, - H, with the sample statistics for mean cholesterol content of a hamburger from two fast food chains and confidence interval construction formula below. Assume the populations are approximately normal with unequal variances Stats X, = 98 mg, s,= 3.81 mg, n, = 14 x = 65 mg, s, =222 mg, n, =20 Confidence interval when variances are not equal +t. n2 d.f. is the smaller of n, - 1 or n, - 1 Enter the endpoints of the interval
IID Suppose X1, ..., X, N(u, o?). Construct a 95% confidence interval for o? when u is known.
Refer to the below table. Using an alpha = 0.05, test the claim that IQ scores are the same for children in three different blood lead level groups: low lead level, medium lead level, and high lead level). One-Way Analysis of Variance Summary Table for IQ Measurements for Children among Three Blood Lead Level Groups: Low Lead Level, Medium Lead Level, and High Lead Level. Source df SS MS F p Between-group (treatment) 2 469.1827 2677.864 2.30 0.104 Within-group (error) 118 203.6918 11745.05 Total 120
The authors of the paper "Statistical Methods for Assessing Agreement Between Two Methods of Clinical Measurement"† compared two different instruments for measuring a person's ability to breathe out air. (This measurement is helpful in diagnosing various lung disorders.) The two instruments considered were a Wright peak flow meter and a mini-Wright peak flow meter. Seventeen people participated in the study, and for each person air flow was measured once using the Wright meter and once using the mini-Wright meter. Subject Mini-WrightMeter WrightMeter Subject Mini-WrightMeter WrightMeter 1 512 494 10 445 433 2 430 395 11 432 417 3 520 516 12 626 656 4 428 434 13 260 267 5 500 476 14 477 478 6 600 557 15 259 178 7 364 413 16 350 423 8 380 442 17 451 427 9 658 650 (a) Suppose that the Wright meter is considered to provide a better measure of air flow, but the mini-Wright meter is easier to transport and to use. If the two types of meters produce…
Find the value of ta/2 given a. 37 for the 85% confidence interval for the mean b. n = 15 for the 94% confidence interval for the mean

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