R language: Create a bar chart that shows the average tip by day-from Thursday to Sunday.totbill16.9910.3421.0123.6879220.2915.7739.4219.8218.71127413.0016.4020.5316.4728.9722.495.7516.3222.7540.1727:281013.503.314.082753:184.00201smokerFNoM NoNoM NoM NoF NoFNoMNoMNoM YesFYesFYes2002.50F Yes4.00 M Yes3.00 M Yes3.50 M NoNo100 FYes4.30FYes3.25F NoM YesYes4.00 MSunSunSunSatSetSetThuThuThuThuThuThuFriFriPriFriFritimeNightNightNightNightDay2Night2Night 2Night 2NightNightDay233NightNight4232223Night 2Night222Night 2NightNight42

Here is the R code of the above problem. Here is the dataset. CSV File…

Answered: language: Create a bar chart that shows…

Computer Networking: A Top-Down Approach (7th Edition)

7th Edition

ISBN:9780133594140

Author:James Kurose, Keith Ross

Publisher:James Kurose, Keith Ross

Chapter1: Computer Networks And The Internet

Section: Chapter Questions

Problem R1RQ: What is the difference between a host and an end system? List several different types of end...

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Dextra Computing sells merchandise for $6,000 cash on September 30 (cost of merchandise is $3,900). Dextra collects 5% sales tax. Record the entry for the $6,000 sale and its sales tax. Also record the entry that shows Dextra sending the sales tax on this sale to the government on October 15.
Description i What is timestamp? Note that we have only timestamps, which ALWAYS contain yyyy-mm-dd as a date, hh:mm:ss as a time, and +/-zzzz as a timezone. time 2017-10-14 00:11:20 +0000 date time zone 12345 + timeconverter.py 1 def convert_time(timestamp): #NOTE: COMPLETE THE CODE FROM HERE! 6 #DO NOT MODIFY THE CONTENT HERE: 7 def print_result(hour, minute): 8 9 print("The time is {}:{}".format(hour, minute)) 10 #DO NOT MODIFY THE CONTENT HERE: 11 timestamp_list = ['2017-10-14 00:11:20 +0000', 12 '2022-03-24 07:22:16 -0400' Topic: Timestamp Converter Write a program timeconverter.py that has two functions: 1) The function convert_time : for extracting the hour and minute from a timestamp and 2) The function print_result: for printing the results. Note that the two functions should be called under the loop. 1) The function convert_time should: 1. take the timestamp from the function call, 2. separate time from date and time zone, 3. split it into hour, minute and seconds, 4. extract…
wyd? \
reprint the number of seconds entered when displaying the converted days, hours, minutes & seconds.
Is the following code for a wall mural a valid UPC number? If not, what should the check digit be in order to make this a valid UPC code> 0 88085 10811 4
In cell H2, get the unique Area values using UNIQUE(). In column I, use COUNTIF() to get the count of each Area. Pass the data range from A2 to A45 as absolute addresses, and the filter criteria from H2 to H9. In column J, use COUNTIFS() to get the count of each area with more than 20 Swallow-tails. the first two arguments are the same as the previous step, then add a condition for column D to be greater than 20. Area Locality Skipper Swallowtail White-yellow Blue Brush-footed Area Count of Area Count of Area with 20 Swallowtails Indian Subcontinent Indian Subcontinent 307 94 99 458 482 Western Himalaya Western Himalaya 63 31 42 129 152 Western Himalaya Kangra Hills 25 23 37 56 87 Western Himalaya Shimla Hills 41 21 34 88 115 Western Himalaya Dehradun Valley 22 11 19 42 54 Western Himalaya Mussoorie Hills 54 23 32 88 126 Western Himalaya Mussoorie Town 14 10 13 44 65 Western Himalaya Kumaon Hills 52 26 37 109 147…
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F A E a. b. C. B d. C 8 00 7- 6 5 What do the letters in the box plot above represent? 3- 2 1- D A = Mean, B = Upper Mean Quartile, C = Lower Mean Quartile, D = Inter Quartile Range, E = Minimum, and F = Outliers A = Mean, B = Third Quartile, C = First Quartile, D = Inter Quartile Range, E = Minimum, and F = Outliers A = Median, B = Third Quartile, C = First Quartile, D = Inter Quartile Range, E = Minimum, and F = Outliers A = Median, B = Third Quartile, C = Mean. D = Inter Quartile Range. E =
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Consider the figure below in which a TCP sender and receiver communicate over a connection in which the segments can be lost. Suppose the initial value of the sequence number is 111 and every segment sent to the receiver each contains 194 bytes. The delay between the sender and receiver is 7 time units, and so the first segment arrives at the receiver at t = 8, and an ACK for this segment arrives at t = 15. And every segment needs to be acknowledged. As shown in the figure, 1 of the 5 segments is lost between the sender and the receiver, but one of the ACKS is lost. Assume there are no timeouts and any out of order segments received are thrown out. TCP sender TCP receiver t= 1 1= 2 data segment t= 3 data segment > t= 4 data segment> t= 5 data segment > data segment P t = 8 -t%= 9 t= 10 = 11 * ACK segment ACK segment ACK segment t= 12 ACK segment t = 15- t= 16 t= 17 t = 18
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