I need hand written n full explanation otherwise I will down vote Question 5Label each of the following statements as either true or false.A. The degree of sequence similarity in homologous proteins correlates to the closeness ofevolutionary relationships.B. Positions that are highly conserved between homologous proteins contribute little to thestructure and function of the protein.C. Positions that are highly variable between homologous proteins are the results of random geneticdrift.D. Positions that are highly variable between homologous proteins tend to be involved in thefunction of the protein.A[ Choose )( Choose )B.TrueFalse[ Choose )D.[ Choose )

Proteins that belong to the same family are called homologous proteins. Proteins that have some…

Answered: Label each of the following statements…

Biochemistry

9th Edition

ISBN:9781319114671

Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Chapter1: Biochemistry: An Evolving Science

Section: Chapter Questions

Problem 1P

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Question: 2. Genes in the same species that have similar related functions are: a. paralogous b. orthologous c. homologous d. heterologous 3. Fill in the blanks: The process of [blank] occurs prior to splicing and changes the [ blank ] of the gene potentially producing a new gene with a related function. 1st blank options: ["exon shuffling", "subfunctionalization", "combinatorial action", "pseudogene construction"] 2nd blank options: ["homeodomain", "domain architecture", "orthology", "multigene family"]
Quèstion 2 Which example is describing a "missense" mutation? O The normal amino acid sequence of a protein is Met-Ala-Phe-Tyr and the mutated alele produces an amino acid sequence Met-Ala-Phe-Tyr OThe normal amino acid sequence of a protein is Met-Ala-Phe-Tyr and the mutated allele produces an amino acid sequence Met-Ala-STOP O The normal amino acid sequence of a protein is Met-Ala-Phe-Tyr and the mutated allele produces an amino acid sequence Met-Ala-Phe-Leu AMoving to the next question prein
Question 4: Imagine that you isolated X-receptor proteins from mutant cells with the nonsense mutation in exon 3. You also isolate X-receptor proteins from wild-type (normal) cells. If you ran these protein molecules on a gel which are your predicted results? A В C Ladder Wild-type Mutant Ladder Wild-type Mutant Ladder Wild-type Mutant
Question #3: CRISPR has been used to cure an individual from sickle cell. Below is a Sanger electropherogram of a sequence from a patient without sickle cell and one with sickle cell. Sequence from a normal individual mmmm Sequence from the diseased individual G T GIIC A GC A Se SCIENCEphe A G A SCIENCE SCIENCEphoto G a) Where is the change in the sequence and what is the consequence to the protein sequence of this mutation? b) Below is an image of the normal and diseased quaternary hemoglobin protein. What is different about the protein shape and why does that structure have a huge impact on its function (please name the function!)? Adult haemogBRAR G G G G A G Sickle Cell haemoglobin S Structure a s RARY COLIBRARY c) If you were to use CRISPR to modify the genome of a diseased individual, to which nucleotides might you design your guide RNA? Why? d) RNA Seq is used to determine off-target effects of Cas9 cleavage. Why is this an appropriate tool to determine these effects? e) Data on…
Question 2. From mouse nerve cells you isolate the mouse Tau-gene-containing DNA fragment and hybridize it to the mRNA encoding Tau from the cytoplasm of the same cells. Describe what you see when you look at the molecules under the electron microscope. A. A double-stranded DNA-RNA hybrid with complete overlap of all the sequences. B. A partially double stranded DNA-RNA hybrid molecule containing regions of DNA-RNA overlap representing the mRNA exons, loops where there are introns and tails at the 5' and 3' ends. C. A partially double-stranded molecule containing regions of DNA-RNA overlap representing the mRNA introns, loops where there are introns and tails at the 5' and 3' ends. D. Regions of DNA-RNA overlap representing the mRNA exons and loops where there are introns with no tails at the 5' or 3' ends. E. Two distinct molecules with no overlapping regions. Multiple Choice
QUESTION 6 If the 3 proteins in the blue sample had MW's of [1] 87,000 Daltons, [2] 30,000 Daltons, [3] 15,000 Daltons; what is the MW of the protein in the 2nd band (counting from the origin) of the green sample? O O O O a. about 15,000 daltons b. about 87,000 daltons c. more than 30,000 daltons but less than 87,000 daltons d. about 30,000 daltons Cellular and Molecular Biology (6657
Question 8. How is the green fluorescent protein (GFP) attached to the protein for which it serves as a label allowing that protein's dynamic activities to be tracked? A. The GFP itself is attached directly to the coding region of the gene of the protein being studied. B. A recombinant RNA is produced by attaching the GFP mRNA to the mRNA of the desired protein. C. GFP adheres specifically to the desired protein via weak interactions. D. The coding region of the GFP gene is joined to the coding region of the gene that encodes the protein being studied.
Question 14 Why are long reads the preferred method to sequence repetitive elements? Select the statement that is FALSE. ◇ If a repetitive region is longer than 300 basepairs (the length of a short read) it's impossible to determine the total length. O Long reads are more likely to span repetitive regions on either side, making it easier to map the repetitive regions. O It's hard to determine where short reads should be placed, as they could map to multiple repetitive regions. O Long reads are less error prone and thus better for sequencing overall. Question 15 Which of the following statements is NOT true about GWAS? When identifying alleles associated with a disease, we compare the frequency of an allele in a control group versus a cash group
QUESTION 8 Check all the statements that are TRUE regarding 16S or ITS (microbiome) illumina (NGS) sequencing vs. whole genome illumina (NGS) sequencing. O A. You don't need to trim the reads for 16S sequencing, but you do for whole genome sequencing. O B. Whole genome sequencing files will have more reads in them because genomes are bigger than 165 amplicons. O C. The read alignment and contig assembly steps would probably be harder for whole genome sequencing. O D. The 165 molecules being sequenced are always DNA, while for whole genome sequencing they could be RNA or DNA going into the illumina sequencer. O E. NGS for 16S and whole genome sequencing can both use sample indexes/barcodes to maximize efficiency. O F. Whole genome sequencing doesn't necessarily require you to know any of the sequences/targets before hand to design specific primers for.
Determine which statements could be used as evidence to support the argument that “DNA influences the proteins that are made” and which statements are just facts. [Select all that apply.] Group of answer choices The symptoms of sickle cell anemia may not appear in individuals who only carry one HbS allele, but are always apparent when both alleles are HbS. If oxygen is removed from red blood cells made by two HbS alleles, the cell will form a sickle shape. The HBB gene that makes beta-globin has several abnormal alleles, including HbS, HbC, and HbE. Sickle cell disease has been successfully treated using bone marrow transplantation in children and adults.
Question 7. What are the first three amino acids in the protein that is produced from this gene? -35 sequence Pribnow box 5' GATTCCGTATTACAGCATAGGCTATATTCACGTGGATGGCTAGT... 3' 3' СТААGGCAТААTGTCGTATСCGATATAAGTGCACCTАCCGAТСА. .. 5' Start site
QUESTION 21 Choose each of the characteristic(s) of all RNA polymerases from the list below. A. elongation adds new ribonucleotides to the 3-OH B. requires a primer to initiate synthesis C. have 3' to 5' exonuclease activity D. adds nucleotides based on sequence complementarity to a template E. have 5' to 3' polymerase activity O F. elongation adds new ribonucleotides to the 2'-OH G. have 3' to 5' polymerase activity

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