1. A population consist of 1, 2, 3 and a sample size of 2 will be taken without replacement.Population MeanPopulation VariancePopulation StandardDeviationSampleP(X)X. P(X) x-H (X-)P). (X- )| =Sample Mean of sampling Sample Variance of sampling Sample Standard Deviationof sampling distributiondistributiondistribution

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Answered: LA population consist of 1, 2, 3 and a…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Age - X Number of meal in a day - Y Frequency of snack in a day - Z. Can we conclude that X, Y and Z follow a normal distribution? Why?
H0 : =150.00 kPa H1 :>150.00 kPa b) α= 0.01; sample variance : 1300 (freq. table ) sample deviation : 36.0555 (freq. table ) Calculation of Data Mean of the results= = 6700/50 =134 Mid Range of the results= (217.32+46.32)/2= 131.82 Range = (217.32-46.32) = 171 Modal Class= Class 121-145 with the highest frequency of 15 Median of the sorted set of data = 132.25 Mode = there are not clear modes In the samples. Sample variance S o= 1300 Sample deviation: S =36.55
[STATISTICS] How do you solve this? Conclusion of confidence intervalThe data is given
z-Scores and Area under the CurveA researcher collected data on adults using an intelligence test. The data for these adults were approximately normally distributed with the following mean and standard deviation mean = 102pointsstandard deviation = 13points Use this information and the online normal distribution calculator to answer the questions below. Round your percents to two decimal places. Note: Use z-scores rounded to 2 decimal places and the standard normal distribution to avoid roundoff errors.Normal CalculatorIf an adult is randomly selected from the study, what is the probability the adult scored between 113points and 125points? ______%If an adult is randomly selected from the study, what is the probability the adult scored less than 110.7points? %If an adult is randomly selected from the study, what is the probability the adult scored more than 127.7points? _______%If an adult is randomly selected from the study, what is the probability the adult scored less than 67.4points…
CI on Mean, Variance Unknown, Prediction and Tolerance Interval A CNC (computer numerical control) machine produces iron automobile crankshafts. Samples are measured and the inner diameter are found to be 1.01,0.97, 1.03, 1.04,0.99, 0.98,0.99, 1.01, and 1.03 centimeters. For all computations, assume an approximately normal distribution. The sample mean and standard deviation for the given data are 1.0056, and s = 0.0246. Find a 99% confidence interval on the mean of diameter. Compute a 99% prediction interval on a measured diameter of a single crankshaft piece taken from the machine. Find the 99% tolerance limits that will contain most of the metal pieces produced by the CNC machine. a. Insufficient data to compute. Missing the sample size n b.CI on the mean: 0.9781 < µ < 1.0331. Prediction Interval: 0.9186 < Xn+1s 1.0926. Tolerance Interval (0.8937 and 1.1175) C. CI on the mean: 0.970 < µ < 1.9845. Prediction Interval: 0.9186 < Xn+1s 1.0926. Tolerance Interval (0.8937 and 1.1175) d.…
Assume the samples are random and independent, the populations are nomally distributed, and the population variances are equal. The table available below shows the prices (in dollars) for a sample of automobile batteries. The prices are classified according to battery type. At a = 0.10, is there enough evidence conclude that at least one mean battery price is different from the others? Complete parts (a) through (e) below. E Click the icon to view the battery cost data. (a) Let u1. P2. H3 represent the mean prices for the group size 35, 65, and 24/24F respectively. Identify the claim and state Ho and H. H Cost of batteries by type The claim is the V hypothesis. Group size 35 Group size 65 Group size 24/24F 101 111 121 124 D 146 173 182 278 124 140 141 89 (b) Find the critical value, Fo, and identify the rejection region. 90 79 84 The rejection region is F Fo, where Fo = (Round to two decimal places as needed.) (c) Find the test statistic F. Print Done F= (Round to two decimal places as…
17. How many observations are there?
The heights of fully grown trees of a specific species are normally distributed, with a mean of 64.0 feet and a standard deviation of 6.50 feet. Random samples of size 19 are drawn from the population. Use the central limit theorem to find the mean and standard error of the sampling distribution. Then sketch a graph of the sampling distribution. Question content area bottom Part 1 The mean of the sampling distribution is μx=enter your response here . The standard error of the sampling distribution is σx=enter your response here . (Round to two decimal places as needed.) Part 2 Choose the correct graph of the sampling distribution below. A. 64.0 77.0 51.0 x A normal curve is over a horizontal x overbar axis labeled from 51.0 to 77.0 in increments of 6.5 and is centered on 64.0. A vertical line segment extends from the horizontal axis to the curve at 64.0. B. 0 2 -2 x A normal curve…
Assuming variance > 1, which of the following must be true? The sample variance is calculated based on the sample size rather than the degrees of freedom The data are normally distributed Standard deviation < variance The model will explain more than 50% of the variance of the dependent variable
Population values: 2, 4, 6 μ = Population mean = Population standard deviation = deviation and not the sample standard deviation. Sampling distribution of size n = 2: 2. Ordered Possible Samples size 2 4₁ 6, 4 6 4 2 2,2 2,4 4,2 4,6 1.63 6,4 6,6 (Round to two places after the decimal). Make sure to enter the population standard 2 4 5 5 Sample Mean 3 4 3 4
Statistical Tables (r, 4, F and Chi-Square) Standard Normal Distributicn Table (2S0) Standard Normal Distribution Table (220) Chi-Square Distribution Table FDistribution Table (a.01) F Distribution Table (a-05) t Distribution Table (d-1,2,35) FDistribution (oa- 025) FDistribution Table (a- 10) 1 Distribution Table (df-36, 37,0) Grocery Price Comparison: Some grocery stores run big sales on selected items, but regular pricing is higher. Some have better every-day pricing but then run fewer sales Amid COVID-19 pandemic, a consumer agency decided to test if the mean grocery prices are significantly different among ie three popular grocery chains in Edmonton and Calgary The weekly total for four consecutive weeks (rounded to the nearest dollar) based on the prices of 100 every-day use items for each of the stores is provided in the following table: Safeway Real Canadian Superstore Save On Foods 798 752 767 781 729 795 763 697 742 817 744 796 1. Assuming that all the assumptions required to…
CI on Mean, Variance Unknown, Prediction and Tolerance Interval A CNC (computer numerical control) machine produces iron automobile crankshafts. Samples are measured and the inner diameter are found to be 1.01,0.97, 1.03, 1.04, 0.99, 0.98,0.99, 1.01, and 1.03 centimeters. For all computations, assume an approximately normal distribution. The sample mean and standard deviation for the given data are 1.0056, and s = 0.0246. Find a 99% confidence interval on the mean of diameter. Compute a 99% prediction interval on a measured diameter of a single crankshaft piece taken from the machine. Find the 99% tolerance limits that will contain most of the metal pieces produced by the CNC machine. a. Insufficient data to compute. Missing the sample size n b. CI on the mean: 0.9781 < µ< 1.0331. Prediction Interval: 0.9186

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