L/2 0 Ay -L/2 Y 02 a α1 T Р P ΔΕ ΔΕ, 1. 2. kQ L -(cosa 2 - cos α1) 5. kQ T -(cosa 2 - cos α₁) kQ 3. -(cosa₁ - cos a2) Lr kQ 4. -(cos a2 - cos a1) Lr kQ T -(cosa₁ - cos α₂) kQ 6. -(cosa₁ - cos α₂) L
L/2 0 Ay -L/2 Y 02 a α1 T Р P ΔΕ ΔΕ, 1. 2. kQ L -(cosa 2 - cos α1) 5. kQ T -(cosa 2 - cos α₁) kQ 3. -(cosa₁ - cos a2) Lr kQ 4. -(cos a2 - cos a1) Lr kQ T -(cosa₁ - cos α₂) kQ 6. -(cosa₁ - cos α₂) L
Related questions
Question
Transcribed Image Text:L/2
0
Ay
-L/2.
02
a
α1
T
ΔΕ
P ΔΕ,
(Qdy/L)
Consider a uniformly charged thin rod with
total charge Q and length L. It is aligned
along the y-axis and centered at the origin
(see fig 8-3hw). We wish to determine the
field at P due to the charges on the rod.
2
Because the rod is centered at the origin,
symmetry tells us the electric field at P must
point in the direction. Based on the differ-
ential form
sin a,
dE,= k
determine the integrated expression for E, at
P.
{Hint: use the math identity dy/p² = da/r.
This identity can be derived using the geo-
metric relation tana = r/(-y) (1), and the
calculus identity dtan a/da = sec² a = p²/y²
(2).}
1.
2.
kQ
L
5.
-(cos a2 - cos α₁)
6.
kQ
r
kQ
3. (cos α₁ - cos a₂)
Lr
-(cosa 2 - cos α₁)
kQ
4. -(cos a2 - cos α₁)
Lr
kQ
r
kQ
L
(cosa₁ - cos a₂)
(cos α₁ - cos a₂)
Expert Solution
Step 1: Introduction
Introduction:- When the rod has a charge on the rod it shows an attractive or repulsive nature to another object.
Given:- Uniformly charged thin rod with length and total charge.
To determine:- The electric field at point 
Step by step
Solved in 3 steps with 9 images
