(L11) A thin 0.120 m copper rod on the x-y plane and parallel to the x axis moves with a constant velocity of 4.17 m/s in the +y direction as shown in the figure. There is a uniform magnetic field 5.84E-2 T everywhere in space pointing in the −z direction (into the page). The electric potential is measured to be Va at point a and V at point b. What is the potential difference Va-Vb (write down the sign and magnitude)? +y +zO Vb Va +x

College Physics
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Chapter1: Units, Trigonometry. And Vectors
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### Problem Description: Moving Copper Rod in Magnetic Field

A thin 0.120 m copper rod on the \( x \)-\( y \) plane and parallel to the \( x \)-axis moves with a constant velocity of 4.17 m/s in the \( +y \) direction, as shown in the figure below. There is a uniform magnetic field of 0.0584 T everywhere in space pointing in the \( -z \) direction (into the page). The electric potential is measured to be \( V_a \) at point \( a \) and \( V_b \) at point \( b \). What is the potential difference \( V_a - V_b \)? (Make sure to write down the sign and magnitude).

#### Diagram Explanation:
- The diagram features a horizontal rod on the \( x \)-\( y \) plane, indicated as black line.
- The \( y \)-axis is marked with positive values upwards (\( +y \)).
- The \( x \)-axis is marked with positive values to the right (\( +x \)).
- The magnetic field (\( B \)) is shown to be directed into the page, represented symbolically with a circle and a cross (\( +z \)).
- Points \( a \) and \( b \) are labeled on the rod, with point \( a \) on the right side and point \( b \) on the left side.
- The velocity vector (\( v \)) is shown pointing upwards along the \( +y \)-axis.

#### Given Data:
- Length of the rod (\( L \)) = 0.120 m
- Velocity (\( v \)) = 4.17 m/s in the \( +y \) direction
- Magnetic field (\( B \)) = 0.0584 T, in the \( -z \) direction (into the page)
- Electric potentials: \( V_a \) at point \( a \) and \( V_b \) at point \( b \)

#### Objective:
Calculate the potential difference \( V_a - V_b \).

### Solution:

The potential difference induced in the rod moving through the magnetic field can be calculated using the formula for motional emf (electromotive force):
\[ \mathcal{E} = vBL \]

Where:
- \( v \) is the velocity
- \( B \) is the magnetic field strength
- \( L \) is the
Transcribed Image Text:### Problem Description: Moving Copper Rod in Magnetic Field A thin 0.120 m copper rod on the \( x \)-\( y \) plane and parallel to the \( x \)-axis moves with a constant velocity of 4.17 m/s in the \( +y \) direction, as shown in the figure below. There is a uniform magnetic field of 0.0584 T everywhere in space pointing in the \( -z \) direction (into the page). The electric potential is measured to be \( V_a \) at point \( a \) and \( V_b \) at point \( b \). What is the potential difference \( V_a - V_b \)? (Make sure to write down the sign and magnitude). #### Diagram Explanation: - The diagram features a horizontal rod on the \( x \)-\( y \) plane, indicated as black line. - The \( y \)-axis is marked with positive values upwards (\( +y \)). - The \( x \)-axis is marked with positive values to the right (\( +x \)). - The magnetic field (\( B \)) is shown to be directed into the page, represented symbolically with a circle and a cross (\( +z \)). - Points \( a \) and \( b \) are labeled on the rod, with point \( a \) on the right side and point \( b \) on the left side. - The velocity vector (\( v \)) is shown pointing upwards along the \( +y \)-axis. #### Given Data: - Length of the rod (\( L \)) = 0.120 m - Velocity (\( v \)) = 4.17 m/s in the \( +y \) direction - Magnetic field (\( B \)) = 0.0584 T, in the \( -z \) direction (into the page) - Electric potentials: \( V_a \) at point \( a \) and \( V_b \) at point \( b \) #### Objective: Calculate the potential difference \( V_a - V_b \). ### Solution: The potential difference induced in the rod moving through the magnetic field can be calculated using the formula for motional emf (electromotive force): \[ \mathcal{E} = vBL \] Where: - \( v \) is the velocity - \( B \) is the magnetic field strength - \( L \) is the
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