Kc = 0.040 for the system below at 450 oC. If a reaction is initiated with 0.40 mole of Cl2 and 0.40 mole of PCl3 in a 2.0 liter container, what is the equilibrium concentration of Cl2 in the same system? PCl5(g) ⇌ PCl3(g) + Cl2(g)
Kc = 0.040 for the system below at 450 oC. If a reaction is initiated with 0.40 mole of Cl2 and 0.40 mole of PCl3 in a 2.0 liter container, what is the equilibrium concentration of Cl2 in the same system? PCl5(g) ⇌ PCl3(g) + Cl2(g)
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Kc = 0.040 for the system below at 450 oC. If a reaction is initiated with 0.40 mole of Cl2 and 0.40 mole of PCl3 in a 2.0 liter container, what is the equilibrium concentration of Cl2 in the same system?
PCl5(g) ⇌ PCl3(g) + Cl2(g)
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![Expert Solution
Step 1
Given :
Kc = 0.040
Step 2
Calculations:
PCI3 (g) + Cl2(g)=PC15(g) Initial :
0.2
0.2
OAt equi: 0.20-x
0.20-х х Кс %3DPCІЗ]
[Cl2][PCI5]
0.040x = 0.04 + x2 - 0.40x 0= x2 + 0.04 - 0.44 x x = 0.311652, 0.128348[Cl2] = 0.20-
Since Kc is given for reverse reaction. 0.040 = [0.20-
x]2x
x = 0.20- 0.128348 =0.0717M](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6ada53f7-d108-4ff9-920e-f8297ca83713%2F973269f9-2fcb-4f5f-b7b6-e301fc529082%2F9h24ap_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Expert Solution
Step 1
Given :
Kc = 0.040
Step 2
Calculations:
PCI3 (g) + Cl2(g)=PC15(g) Initial :
0.2
0.2
OAt equi: 0.20-x
0.20-х х Кс %3DPCІЗ]
[Cl2][PCI5]
0.040x = 0.04 + x2 - 0.40x 0= x2 + 0.04 - 0.44 x x = 0.311652, 0.128348[Cl2] = 0.20-
Since Kc is given for reverse reaction. 0.040 = [0.20-
x]2x
x = 0.20- 0.128348 =0.0717M
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