Kb is 3.63 °C/m.) A Top: KbpMsdute AT: (61.82C - 61.93°C): 0.23°C mass of hexa chlorophene: 0.6409 mass of chlowform: 25g Molal boiling point elevahen Constant moles molav mas5 of chloroform is 3.63 °C/m ATbe Кыр (O.25e エ632/m)0.0し33しm %3D msdute: Khp -molal boiling point elevahion Consknt 259/ lkg 0.0633しm -)(0.0154) Ikg mole : mass molar mass 0.015kg 1,584 X10°mol 404 /ml molav mass : A 1.37 M solution of citric acid (H3C6H5O7) in water has a density of 1.10 g/mL. What is mass numbev of nole 1-58X10 mol 4. the mass percent of the solution? Density = 1.10g/mL Molavity molav mass H3 CG Hs07 1.00 X10mL Soln kt0g miL 1.37 mot X 192.13 Mot 2639 (1.08)3)+(7.01)+ (6008X5) +1)G) :1.37M 2635 X 100 : 23.9% 192.13 %3D 5. How many grams of ethylene glycol, C2H4(OH)2, must be added to 5.50 kg of water to lower the freezing point of water from 0.0 °C to -10.0 °C? (This is approximately the situation in the radiator of your car.) Calculate the molality of C2H5OH in a water solution which is prepared by mixing 50.0 mL of C2H5OH with 100.0 mL of H2O at 20°C. The density of C2H5OH is 0.789 g/mL at 20°C and that of water is 0.99970 g/mL. 6.
Kb is 3.63 °C/m.) A Top: KbpMsdute AT: (61.82C - 61.93°C): 0.23°C mass of hexa chlorophene: 0.6409 mass of chlowform: 25g Molal boiling point elevahen Constant moles molav mas5 of chloroform is 3.63 °C/m ATbe Кыр (O.25e エ632/m)0.0し33しm %3D msdute: Khp -molal boiling point elevahion Consknt 259/ lkg 0.0633しm -)(0.0154) Ikg mole : mass molar mass 0.015kg 1,584 X10°mol 404 /ml molav mass : A 1.37 M solution of citric acid (H3C6H5O7) in water has a density of 1.10 g/mL. What is mass numbev of nole 1-58X10 mol 4. the mass percent of the solution? Density = 1.10g/mL Molavity molav mass H3 CG Hs07 1.00 X10mL Soln kt0g miL 1.37 mot X 192.13 Mot 2639 (1.08)3)+(7.01)+ (6008X5) +1)G) :1.37M 2635 X 100 : 23.9% 192.13 %3D 5. How many grams of ethylene glycol, C2H4(OH)2, must be added to 5.50 kg of water to lower the freezing point of water from 0.0 °C to -10.0 °C? (This is approximately the situation in the radiator of your car.) Calculate the molality of C2H5OH in a water solution which is prepared by mixing 50.0 mL of C2H5OH with 100.0 mL of H2O at 20°C. The density of C2H5OH is 0.789 g/mL at 20°C and that of water is 0.99970 g/mL. 6.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
How many grams of ethylene glycol, C2H4(OH)2, must be added to 5.50 kg of water to lower the freezing point of water from 0.0 degrees Celsius to -10.0 degrees Celsius?
Transcribed Image Text:Kb is 3.63 °C/m.)
A Top: KbpMsdute
AT: (61.82C - 61.93°C): 0.23°C
mass of hexa chlorophene: 0.6409
mass of chlowform: 25g
Molal boiling point elevahen Constant moles molav mas5
of chloroform is 3.63 °C/m
ATbe
Кыр
(O.25e
エ632/m)0.0し33しm
%3D
msdute:
Khp -molal boiling point
elevahion Consknt
259/ lkg
0.0633しm
-)(0.0154)
Ikg
mole :
mass
molar mass
0.015kg
1,584 X10°mol
404 /ml
molav mass :
A 1.37 M solution of citric acid (H3C6H5O7) in water has a density of 1.10 g/mL. What is
mass
numbev of nole
1-58X10 mol
4.
the mass percent of the solution?
Density = 1.10g/mL
Molavity
molav mass H3 CG Hs07
1.00 X10mL Soln kt0g
miL
1.37 mot X
192.13
Mot
2639
(1.08)3)+(7.01)+ (6008X5) +1)G)
:1.37M
2635
X 100
: 23.9%
192.13
%3D
5.
How many grams of ethylene glycol, C2H4(OH)2, must be added to 5.50 kg of water to
lower the freezing point of water from 0.0 °C to -10.0 °C? (This is approximately the
situation in the radiator of your car.)
Calculate the molality of C2H5OH in a water solution which is prepared by mixing 50.0
mL of C2H5OH with 100.0 mL of H2O at 20°C. The density of C2H5OH is 0.789 g/mL at
20°C and that of water is 0.99970 g/mL.
6.
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