K. for the reaction of hydrogen and iodine to produce hydrogen iodide. H2(g) + I(g) = 2HI(g) is 54.3 at 430°C. Calculate the equilibrium concentrations of H,, I, and HI at 430°C if the initial concentrations are [H2] = [Ll 0 M, and [HI] = 0.523 M. %3D [H] = M M [HI] = M

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**Equilibrium Concentration Calculation for the Reaction of Hydrogen and Iodine**

The equilibrium constant \( K_c \) for the reaction of hydrogen and iodine to produce hydrogen iodide is provided. The balanced chemical equation is:

\[ \text{H}_2(g) + \text{I}_2(g) \rightleftharpoons 2\text{HI}(g) \]

At 430°C, \( K_c \) is 54.3. You need to calculate the equilibrium concentrations of \(\text{H}_2\), \(\text{I}_2\), and \(\text{HI}\) at this temperature, given the initial concentrations:

- \([\text{H}_2] = 0 \, \text{M}\)
- \([\text{I}_2] = 0 \, \text{M}\)
- \([\text{HI}] = 0.523 \, \text{M}\)

**Fill in the Equilibrium Concentrations:**

- \([\text{H}_2] = \) _____ M
- \([\text{I}_2] = \) _____ M
- \([\text{HI}] = \) _____ M

**Instructions for Calculation:**

1. **Set up an ICE table (Initial, Change, Equilibrium)**
   - Determine initial concentrations.
   - Calculate changes in concentration using an unknown variable.
   - Establish expressions for equilibrium concentrations.

2. **Apply the Equilibrium Constant Expression:**

   \[
   K_c = \frac{[\text{HI}]^2}{[\text{H}_2][\text{I}_2]}
   \]

3. **Solve for the unknown concentrations to find equilibrium values.**

Ensure that these calculations align with stoichiometric relationships and the given equilibrium constant.
Transcribed Image Text:**Equilibrium Concentration Calculation for the Reaction of Hydrogen and Iodine** The equilibrium constant \( K_c \) for the reaction of hydrogen and iodine to produce hydrogen iodide is provided. The balanced chemical equation is: \[ \text{H}_2(g) + \text{I}_2(g) \rightleftharpoons 2\text{HI}(g) \] At 430°C, \( K_c \) is 54.3. You need to calculate the equilibrium concentrations of \(\text{H}_2\), \(\text{I}_2\), and \(\text{HI}\) at this temperature, given the initial concentrations: - \([\text{H}_2] = 0 \, \text{M}\) - \([\text{I}_2] = 0 \, \text{M}\) - \([\text{HI}] = 0.523 \, \text{M}\) **Fill in the Equilibrium Concentrations:** - \([\text{H}_2] = \) _____ M - \([\text{I}_2] = \) _____ M - \([\text{HI}] = \) _____ M **Instructions for Calculation:** 1. **Set up an ICE table (Initial, Change, Equilibrium)** - Determine initial concentrations. - Calculate changes in concentration using an unknown variable. - Establish expressions for equilibrium concentrations. 2. **Apply the Equilibrium Constant Expression:** \[ K_c = \frac{[\text{HI}]^2}{[\text{H}_2][\text{I}_2]} \] 3. **Solve for the unknown concentrations to find equilibrium values.** Ensure that these calculations align with stoichiometric relationships and the given equilibrium constant.
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