K. for the reaction of hydrogen and iodine to produce hydrogen iodide. H2(g) + I(g) = 2HI(g) is 54.3 at 430°C. Calculate the equilibrium concentrations of H,, I, and HI at 430°C if the initial concentrations are [H2] = [Ll 0 M, and [HI] = 0.523 M. %3D [H] = M M [HI] = M
K. for the reaction of hydrogen and iodine to produce hydrogen iodide. H2(g) + I(g) = 2HI(g) is 54.3 at 430°C. Calculate the equilibrium concentrations of H,, I, and HI at 430°C if the initial concentrations are [H2] = [Ll 0 M, and [HI] = 0.523 M. %3D [H] = M M [HI] = M
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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![**Equilibrium Concentration Calculation for the Reaction of Hydrogen and Iodine**
The equilibrium constant \( K_c \) for the reaction of hydrogen and iodine to produce hydrogen iodide is provided. The balanced chemical equation is:
\[ \text{H}_2(g) + \text{I}_2(g) \rightleftharpoons 2\text{HI}(g) \]
At 430°C, \( K_c \) is 54.3. You need to calculate the equilibrium concentrations of \(\text{H}_2\), \(\text{I}_2\), and \(\text{HI}\) at this temperature, given the initial concentrations:
- \([\text{H}_2] = 0 \, \text{M}\)
- \([\text{I}_2] = 0 \, \text{M}\)
- \([\text{HI}] = 0.523 \, \text{M}\)
**Fill in the Equilibrium Concentrations:**
- \([\text{H}_2] = \) _____ M
- \([\text{I}_2] = \) _____ M
- \([\text{HI}] = \) _____ M
**Instructions for Calculation:**
1. **Set up an ICE table (Initial, Change, Equilibrium)**
- Determine initial concentrations.
- Calculate changes in concentration using an unknown variable.
- Establish expressions for equilibrium concentrations.
2. **Apply the Equilibrium Constant Expression:**
\[
K_c = \frac{[\text{HI}]^2}{[\text{H}_2][\text{I}_2]}
\]
3. **Solve for the unknown concentrations to find equilibrium values.**
Ensure that these calculations align with stoichiometric relationships and the given equilibrium constant.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fcb9e9c53-4f67-4b94-a326-480d7802c16b%2Ffd47c6f4-11f2-498f-b37d-0d27d621240a%2F8izss7j_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Equilibrium Concentration Calculation for the Reaction of Hydrogen and Iodine**
The equilibrium constant \( K_c \) for the reaction of hydrogen and iodine to produce hydrogen iodide is provided. The balanced chemical equation is:
\[ \text{H}_2(g) + \text{I}_2(g) \rightleftharpoons 2\text{HI}(g) \]
At 430°C, \( K_c \) is 54.3. You need to calculate the equilibrium concentrations of \(\text{H}_2\), \(\text{I}_2\), and \(\text{HI}\) at this temperature, given the initial concentrations:
- \([\text{H}_2] = 0 \, \text{M}\)
- \([\text{I}_2] = 0 \, \text{M}\)
- \([\text{HI}] = 0.523 \, \text{M}\)
**Fill in the Equilibrium Concentrations:**
- \([\text{H}_2] = \) _____ M
- \([\text{I}_2] = \) _____ M
- \([\text{HI}] = \) _____ M
**Instructions for Calculation:**
1. **Set up an ICE table (Initial, Change, Equilibrium)**
- Determine initial concentrations.
- Calculate changes in concentration using an unknown variable.
- Establish expressions for equilibrium concentrations.
2. **Apply the Equilibrium Constant Expression:**
\[
K_c = \frac{[\text{HI}]^2}{[\text{H}_2][\text{I}_2]}
\]
3. **Solve for the unknown concentrations to find equilibrium values.**
Ensure that these calculations align with stoichiometric relationships and the given equilibrium constant.
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