N₂O4 (g) = 2NO₂(g) K = 6.14 x 10-3 @ 298 K A sealed 2.0 L container initially holds 5.0 moles N2O4 and 0.050 mole NO2. Determine the concentrations at equilibrium. What is the concentration of NO2 at equilibrium? [NO₂] = [?] M [NO₂], M Enter

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**Equilibrium Concentrations Calculation for NO₂**

**Chemical Reaction:**

\[ \text{N}_2\text{O}_4\text{ (g)} \rightleftharpoons 2\text{NO}_2\text{ (g)} \]

**Equilibrium Constant:**

\[ K = 6.14 \times 10^{-3} \text{ at } 298 \text{ K} \]

**Initial Conditions:**

A sealed 2.0 L container initially holds:
- 5.0 moles of \(\text{N}_2\text{O}_4\)
- 0.050 moles of \(\text{NO}_2\)

**Problem Statement:**

Determine the concentrations at equilibrium. What is the concentration of \(\text{NO}_2\) at equilibrium?

\[ [\text{NO}_2] = ? \text{ M} \]

**Diagram:**

An interactive element is present at the bottom of the image for inputting the equilibrium concentration of \(\text{NO}_2\) in molarity (M). It includes a text box labeled `[NO₂], M` and a blue 'Enter' button to submit the value. 

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To find the equilibrium concentrations, the following steps are usually performed:

1. **Initial Concentrations:**
   - \(\text{N}_2\text{O}_4\): \(\frac{5.0 \text{ moles}}{2.0 \text{ L}} = 2.5 \text{ M}\)
   - \(\text{NO}_2\): \(\frac{0.050 \text{ moles}}{2.0 \text{ L}} = 0.025 \text{ M}\)

2. **Set up the ICE Table (Initial, Change, Equilibrium):**

   |               | \( \text{N}_2\text{O}_4 \)   | \(\text{NO}_2\)   |
   |---------------|--------------------|-------------------|
   | Initial (M)   | 2.5                | 0.025             |
   | Change (M)    | - x                | + 2x              |
   | Equilibrium (M)| 2.5 - x            | 0.025 + 2x        |

3. **Expression for the Equ
Transcribed Image Text:**Equilibrium Concentrations Calculation for NO₂** **Chemical Reaction:** \[ \text{N}_2\text{O}_4\text{ (g)} \rightleftharpoons 2\text{NO}_2\text{ (g)} \] **Equilibrium Constant:** \[ K = 6.14 \times 10^{-3} \text{ at } 298 \text{ K} \] **Initial Conditions:** A sealed 2.0 L container initially holds: - 5.0 moles of \(\text{N}_2\text{O}_4\) - 0.050 moles of \(\text{NO}_2\) **Problem Statement:** Determine the concentrations at equilibrium. What is the concentration of \(\text{NO}_2\) at equilibrium? \[ [\text{NO}_2] = ? \text{ M} \] **Diagram:** An interactive element is present at the bottom of the image for inputting the equilibrium concentration of \(\text{NO}_2\) in molarity (M). It includes a text box labeled `[NO₂], M` and a blue 'Enter' button to submit the value. -------------------------------------------------------------------------------------------------- To find the equilibrium concentrations, the following steps are usually performed: 1. **Initial Concentrations:** - \(\text{N}_2\text{O}_4\): \(\frac{5.0 \text{ moles}}{2.0 \text{ L}} = 2.5 \text{ M}\) - \(\text{NO}_2\): \(\frac{0.050 \text{ moles}}{2.0 \text{ L}} = 0.025 \text{ M}\) 2. **Set up the ICE Table (Initial, Change, Equilibrium):** | | \( \text{N}_2\text{O}_4 \) | \(\text{NO}_2\) | |---------------|--------------------|-------------------| | Initial (M) | 2.5 | 0.025 | | Change (M) | - x | + 2x | | Equilibrium (M)| 2.5 - x | 0.025 + 2x | 3. **Expression for the Equ
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