PK@2Listed in the data table are IQ scores for a random sample of subjects with medium lead levels in their blood. Also listed are statistics from a study done of IQ scores for a random sample of subjectswith high lead levels. Assume that the two samples are independent simple random samples selected from normally distributed populations. Do not assume that the population standard deviationsare equal. Complete parts (a) and (b) below.Click the icon to view the data table of IQ scores.Help me solve thisSa. Use a 0.01 significance level to test the claim that the mean IQ scores for subjects with medium lead levels is higher than the mean for subjects with high lead levels.What are the null and alternative hypotheses? Assume that population 1 consists of subjects with medium lead levels and population 2 consists of subjects with high lead levels.F2W30²OA H₂: #₁ = 1/₂H₁: Hy #4₂OC. Ho: Hy #4₂H₁: Hy > H₂The test statistic is (Round to two decimal places as needed.)mmandXH#380EDGet more help.C$4QFARFV%5↓FSTGA6BMacBook Air&F6YH&7IQ ScoresN44F7OB. Ho: ₁5₂H₁: Hy > H₂UD. Ho: #₁=4₂H₁: Hy > H₂MMedium Lead Level High Lead Level72n₂ = 11979285879783928I1JPilFaK10011191(9<IDDF9OX2 = 91.088$2= 10.092L)Ocommand4F10P^.:;-IoptionF11{[?1- X+=11Check answer(12)F12}]xdelete\returnshifdrew

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Answered: K Listed in the data table are with…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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This is a friendly reminder about scientific notation. Excel reports very small numbers in scientific notation. For example, 8.15E-05 is typical notation for 8.15 x 10-5. The exponent of -5 means you have to move the decimal five places to the left and fill in with zeroes. What you get is 0.0000815. Here is the Excel output again for the regression of Sales and Experience: Regression Statistics 0.5966 0.3559 0.339 497.9058 Multiple R R Square Adjusted R Square Standard Error Observations ANOVA Regression Residual Total Intercept Experience (months) 40 df 1 38 39 Coefficients 6.6108 SS MS 5205388.04 5205388.04 9420585.51 Standard Error 4250.9742 180.2332 14625973.55 1.4427 247910.15 t Stat 23.586 4.5822 P-value 2.71E-24 4.85E-05 F 20.9971 Lower 95% Upper 95% Significance F 4.85E-05 3886.1113 4615.8372 3.6902 The analyst decides to use an a = 0.05 significance level. Is there a statistically significant relationship between Sales and Experience? 9.5313
Choose the correct answer.If the P-value of a test of significance is 0.999 then:A. the null hypothesis should be rejected.B. the null hypothesis should not be rejected.C. the alternative hypothesis provides a plausible explanation of the data.D. Both A and C are true.
Listed in the accompanying table are heights (in.) of mothers and their first daughters. The data pairs are from a journal kept by Francis Galton. Use the listed paired sample data, and assume that the samples are simple random samples and that the differences have a distribution that is approximately normal. Use a 0.05 significance level to test the claim that there is no difference in heights between mothers and their first daughters. Mother 64.0 66.0 63.0 62.0 66.5 66.0 65.0 60.0 67.0 63.0 Daughter 67.0 66.5 70.5 66.0 61.0 66.0 65.5 65.0 67.0 65.0 In this example, Hd is the mean value of the differences d for the population of all pairs of data, where each individual difference d is defined as the daughter's height minus the mother's height. What are the null and alternative hypotheses for the hypothesis test? Ho: Ha = 0 in. H₁ Hd 0 in. (Type integers or decimals. Do not round.) Identify the test statistic. t= (Round to two decimal places as needed.)
Assume that you want to test the claim that the paired sample data from a for which the mean difference Ha = 0. Give the value of the ttest statistic. 11 13 5 Y 8 6 4 Note: Use three decimal places.
instructor thinks that the mean score is higher. She samples 10 statistics students and obtains the scores: Grades 63.9 68.4 | 69 | 96 64.3 | 63.9 65 69 62.7 68.4 Test grades are believed to be normally distributed. Use a significance level of 5%. A. State the alternative hypothesis: HA: Ou + 65 Ομ 65 B. State the mean of the sample: C. State the standard error of the sample means:
Listed in the accompanying table are heights (in.) of mothers and their first daughters. The data pairs are from a journal kept by Francis Galton. Use the listed paired sample data, and assume that the samples are simple random samples and that the differences have a distribution that is approximately normal. Use a 0.05 significance level to test the claim that there is no difference in heights between mothers and their first daughters. ... Question content area top right Part 1 Mother 62.0 65.0 64.7 65.5 65.0 67.0 66.0 66.5 63.0 58.5 Daughter 68.0 69.0 66.5 63.0 68.0 62.0 66.5 66.7 63.5 66.5 Question content area bottom Part 1 In this example, μd is the mean value of the differences d for the population of all pairs of data, where each individual difference d is defined as the daughter's height minus the mother's height. What are the null and alternative hypotheses for the hypothesis test? H0:…
Find the standardized test , z to test the claim that p1 = p2. The sample statistics listed below are from independent samples.
UBS Wealth Management UK periodically ask their customers to evaluate their financial consultants and services. The higher the customer rating, the better the perceived service. The maximum rating is 7. Independent samples of two financial consultants are given below. Consultant A has 10 years' experience, Consultant B has 1 years' experience. Use α = 0.05 and test to see whether the consultant with more experience has the higher population mean service rating. Consultant A Consultant B N1 = 16 N2 = 10 Mean1 = 6.82 Mean2 = 6.25 S1= 0.64 S2 = 0.75 State the null and alternative hypothesis, Compute the value of the test statistic. What is the p-value? What is your conclusion?
For the following scores from a sample: a. Compute the mean, median and mode for the scores. b. Compute the SS, variance and SD. X f 7 1 6 2 5 2 4 2 3 1 MacBook Air
Refer to the data set in the accompanying table. Assume that the paired sample data is a simple random sample and the differences have a distribution that is approximately normal. Use a significance level of 0.10 to test for a difference between the weights of discarded paper (in pounds) and weights of discarded plastic (in pounds). a. Identify the test statistic. t equals (Round to two decimal places as needed.) b. Identify the P-value. P-value equals (Round to three decimal places as needed.)
Consider the relationship between p-values and significance levels. a. Explain why a value of z-statistic that is significant at the 1% level in a one-sided test is always significant at the 5% level. b. Explain why the reverse is not true. If something is significant at the 5% level in a one-sided test it is not necessarily significant at the 1% level.
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