K C E F1 F2 AC, CE, EG, GI, IK, BD, DF, FH, HJ = 12 m, AZ-14 m, ZB-6 mF_1= 50 kN, F 2 = 50 kN For the truss as shown and the loading indicated. Show the free body diagram for the joint: Olncluded in manual solution ONot made 1.Find the reactions. Reaction at A is: kN. (answer to the nearest whole number) Reaction at K is: kN. (answer to the nearest whole number) C1

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
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C.
G
F1 F2
AC, CE, EG, GI, IK, BD, DF, FH, HJ = 12 m, AZ=14 m, ZB=6 mF_1 = 50 kN, F_2 = 50 kN
For the truss as shown and the loading indicated.
Show the free body diagram for the joint:
Olncluded in manual solution
ONot made
1.Find the reactions.
Reaction at A is:
kN. (answer to the nearest whole number)
Reaction at K is:
kN. (answer to the nearest whole number)
2. Use the method of joints to find the forces in AB and AC.
The force in member AB is:
kN [Tension:+, Compression:-]
2. Use the method of joints to find the forces in AB and AC.
The force in member AB is:
kN [Tension:+, Compression: -]
The force in member AC is:
kN [Tension:+, Compression: -]
3. Find the force in members CE, DE, DF using the method of sections.
The force in member CE is:
kN [Tension:+, Compression: -]
The force in member DE is:
Kn[Tension:+, Compression: -]
The force in member DF is:
kN [Tension:+, Compression: -]
Transcribed Image Text:C. G F1 F2 AC, CE, EG, GI, IK, BD, DF, FH, HJ = 12 m, AZ=14 m, ZB=6 mF_1 = 50 kN, F_2 = 50 kN For the truss as shown and the loading indicated. Show the free body diagram for the joint: Olncluded in manual solution ONot made 1.Find the reactions. Reaction at A is: kN. (answer to the nearest whole number) Reaction at K is: kN. (answer to the nearest whole number) 2. Use the method of joints to find the forces in AB and AC. The force in member AB is: kN [Tension:+, Compression:-] 2. Use the method of joints to find the forces in AB and AC. The force in member AB is: kN [Tension:+, Compression: -] The force in member AC is: kN [Tension:+, Compression: -] 3. Find the force in members CE, DE, DF using the method of sections. The force in member CE is: kN [Tension:+, Compression: -] The force in member DE is: Kn[Tension:+, Compression: -] The force in member DF is: kN [Tension:+, Compression: -]
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